十进制整数文字中不允许有前导零

Question

我收到此错误：

Traceback (most recent call last):
  File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 31, in <module>
    start(fakepyfile,mainpyfile)
  File "/data/user/0/ru.iiec.pydroid3/files/accomp_files/iiec_run/iiec_run.py", line 30, in start
    exec(open(mainpyfile).read(),  __main__.__dict__)
  File "<string>", line 2
    d = {0:00 , 1:11, 2:10, 3:09, 4:08, 5:07, 6:06, 7:05, 8:04, 9:03, 10:02, 11:01, 12:12}
                              ^
SyntaxError: leading zeros in decimal integer literals are not permitted; use an 0o prefix for octal integer

这是我的代码：

x, y = map(int, input().split())
d = {0:00 , 1:11, 2:10, 3:09, 4:08, 5:07, 6:06, 7:05, 8:04, 9:03, 10:02, 11:01, 12:12}
print(d)
print(d[3])

Answer 1

在 Python 中，不能使用带前导零的整数，如

01

、

001

对于您的情况，您可以使用这样的字符串

d = {0: '00', 1: '11', 2: '10', 3: '09', 4: '08', 5: '07', 6: '06', 7: '05', 8: '04', 9: '03', 10: '02', 11: '01', 12: '12'}
print(d)
print(d[3])