我想将用户给定的时间加到另一个时间上,并增加n次
start_time = '7:00' #these values will be taken as string by user
hour_time = '0:30'
increment_var = 5
time_var = datetime.strptime(start_time, '%H:%M')
difference_time = datetime.strptime(hour_time, '%H:%M')
time_var2 = difference_time.time()
尝试过此
timed = timedelta(
hours=time_var2.hour, minutes=time_var2.minute)
for num in range(increment_var):
diffrence = time_var + timed
print(diffrence)
它给了我
1900-01-01 07:30:00
1900-01-01 07:30:00
1900-01-01 07:30:00
1900-01-01 07:30:00
1900-01-01 07:30:00
虽然我期望有类似的东西
1900-01-01 07:30:00
1900-01-01 08:00:00
1900-01-01 08:30:00
1900-01-01 09:00:00
1900-01-01 09:30:00
和与]相同的结果>
for num in range(increment_var):
timed = timedelta(hours=time_var2.hour,
minutes=time_var2.minute)
difference = time_var + timed
print(difference)
我想将用户给定的时间加到另一个时间上,并将其递增n次start_time ='7:00'#这些值将由用户hour_time ='0:30'以string的形式递增inv_var = 5 .. 。
您能看到下面这段代码为什么起作用吗?
您没有在for循环中更新时间