我试图用扑框架插入一行到数据库中的表,当我指派返回值到一个新的变量,我得到了以下错误消息
a value of type future<int> can not be assigned to a variable of type int
这是插入新行的功能
Future<int> addContact(String contact_name, String contact_phone) async {
Database c = await getConnection;
Map<String, dynamic> contact = getMap(contact_name, contact_phone);
return await c.insert("contacts", contact);
}
这里在那里我得到返回的数据
int result=db.addContact(name, phone);
您可以使用FutureBuilder
。下面是一个例子:
@override
Widget build(BuildContext context) {
return new FutureBuilder (
future: loadFuture(), //This is the method that returns your Future
builder: (BuildContext context, AsyncSnapshot snapshot) {
if (snapshot.hasData) {
if (snapshot.data) {
return customBuild(context); //Do stuff and build your screen from this method
}
} else {
//While the future is loading, show a progressIndicator
return new CustomProgressIndicator();
}
}
);
}
要么使用FutureBuilder
或类似这样的东西
int value; //should be state variable. As we want to refresh the view after we get data
@override
Widget build(BuildContext context) {
db.addContact(name, phone).then((value) {
setState(() {this.value = value;});
})
return ....
的addContact功能有一定的操作将返回当操作完成值,所以要完成块这里.....
addContact(contact_name, contact_phone).then((value) {
//this 'value' is in int
//This is just like a completion block
});