如何阅读用C的视频文件

问题描述 投票:0回答:3

我有一个视频文件,并希望阅读并显示结果在另一个文件中。

FILE *fp1,*fp2;

fp1=fopen("FOOTBALL_352x288_30_orig_01.yuv","rb");   
fp2=fopen("FOOTBALL_352x288_30_copy_01.yuv","wb");

while (feof(fp1))
{
  fread(1,sizeof(int),fp1);
  fwrite(fp1,sizeof(int),fp2);
}

fclose(fp1);
fclose(fp2);
c video yuv
3个回答
1
投票

你或多或少想是这样的:

#include <stdlib.h>
#include <stdio.h>

#define BUFFERSIZE 0x8000 // 32k buffer (adapt at will)

int main()
{
  FILE *fp1 = fopen("FOOTBALL_352x288_30_orig_01.yuv", "rb");

  if (fp1 == NULL)
  {
    // display error message to be written
    exit(1);
  }
  FILE *fp2 = fopen("FOOTBALL_352x288_30_copy_01.yuv", "wb");
  if (fp2 == NULL)
  {
    // display error message to be written
    exit(1);
  }    

  for (;;)   // loop for ever
  {
    char buffer[BUFFERSIZE];
    size_t bytesread = fread(buffer, 1, sizeof buffer, fp1);

    // bytesread contains the number of bytes actually read
    if (bytesread == 0)
    {
      // no bytes read => end of file
      break;
    }

    fwrite(buffer, bytesread, 1, fp2);
  }

  fclose(fp1);
  fclose(fp2);
}

免责声明:这是未经测试的代码,但你应该明白我的意思。

还有进一步改进的余地,不是文件的末尾有其他特别实际的读错误(很少发生)没有被正确处理。


0
投票

这是我的解决方案,我测试,它似乎工作,你认为什么家伙

#include <stdio.h>
#include <math.h>
#include <stdint.h>


	
int main(void) {
    FILE *fp1, *fp2;
 
	fp1= fopen("FOOTBALL_352x288_30_orig_01.yuv","rb");
	
	fp2= fopen("FOOTBALL_352x288_30_copy_02.yuv","wb");
   
 
	
int buffer;
while(!feof(fp1))
	{
		fread((void *)&buffer, sizeof(buffer),1,fp1);
		fwrite((void *)&buffer, sizeof(buffer),1,fp2);
		}
  

    fclose(fp1);
    fclose(fp2);
	
	return 0;
}

-1
投票

你想在!feof(fp1)阅读。

FREAD读取到缓存...这里是你的缓冲区? FWRITE写道从该缓冲区的内容。

而你,也不想读sizeof(int),使用的数据类型与指定大小,就像在uint8_t 8位。

uint8_t buffer;

然后,你可以做

fread((void *)&buffer, sizeof(uint8_t), 1, fp1);
fwrite((void *)&buffer, sizeof(uint8_t), 1, fp2);

当然,你应该添加一些错误处理,以及...

另外这是很慢的,当你阅读逐字节:)但是,这是它的基本工作原理。

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