我有一个视频文件,并希望阅读并显示结果在另一个文件中。
FILE *fp1,*fp2;
fp1=fopen("FOOTBALL_352x288_30_orig_01.yuv","rb");
fp2=fopen("FOOTBALL_352x288_30_copy_01.yuv","wb");
while (feof(fp1))
{
fread(1,sizeof(int),fp1);
fwrite(fp1,sizeof(int),fp2);
}
fclose(fp1);
fclose(fp2);
你或多或少想是这样的:
#include <stdlib.h>
#include <stdio.h>
#define BUFFERSIZE 0x8000 // 32k buffer (adapt at will)
int main()
{
FILE *fp1 = fopen("FOOTBALL_352x288_30_orig_01.yuv", "rb");
if (fp1 == NULL)
{
// display error message to be written
exit(1);
}
FILE *fp2 = fopen("FOOTBALL_352x288_30_copy_01.yuv", "wb");
if (fp2 == NULL)
{
// display error message to be written
exit(1);
}
for (;;) // loop for ever
{
char buffer[BUFFERSIZE];
size_t bytesread = fread(buffer, 1, sizeof buffer, fp1);
// bytesread contains the number of bytes actually read
if (bytesread == 0)
{
// no bytes read => end of file
break;
}
fwrite(buffer, bytesread, 1, fp2);
}
fclose(fp1);
fclose(fp2);
}
免责声明:这是未经测试的代码,但你应该明白我的意思。
还有进一步改进的余地,不是文件的末尾有其他特别实际的读错误(很少发生)没有被正确处理。
这是我的解决方案,我测试,它似乎工作,你认为什么家伙
#include <stdio.h>
#include <math.h>
#include <stdint.h>
int main(void) {
FILE *fp1, *fp2;
fp1= fopen("FOOTBALL_352x288_30_orig_01.yuv","rb");
fp2= fopen("FOOTBALL_352x288_30_copy_02.yuv","wb");
int buffer;
while(!feof(fp1))
{
fread((void *)&buffer, sizeof(buffer),1,fp1);
fwrite((void *)&buffer, sizeof(buffer),1,fp2);
}
fclose(fp1);
fclose(fp2);
return 0;
}
你想在!feof(fp1)
阅读。
FREAD读取到缓存...这里是你的缓冲区? FWRITE写道从该缓冲区的内容。
而你,也不想读sizeof(int)
,使用的数据类型与指定大小,就像在uint8_t
8位。
uint8_t buffer;
然后,你可以做
fread((void *)&buffer, sizeof(uint8_t), 1, fp1);
fwrite((void *)&buffer, sizeof(uint8_t), 1, fp2);
当然,你应该添加一些错误处理,以及...
另外这是很慢的,当你阅读逐字节:)但是,这是它的基本工作原理。