我的数据表如下(表1)
Table1
------------------------------------------
ID | IPaddress | Port | Value
----|---------------|-------|-------------
1 | xx.yy.14.15 | 332 | This is good
------------------------------------------
2 | xx.yy.14.15 | 332 | I can work
------------------------------------------
3 | xx.yy.12.12 | 400 | Looks ok
------------------------------------------
4 | xx.yy.12.12 | 400 | can I work
------------------------------------------
5 | xx.yy.12.12 | 400 | Yes, please
-------------------------------------------
6 | xx.yy.14.16 | 401 | How is this
-------------------------------------------
7 | xx.yy.14.16 | 401 | Looks ok
-------------------------------------------
8 | xx.yy.14.16 | 401 | can I work
-------------------------------------------
9 | xx.yy.14.16 | 401 | Yes, please
-------------------------------------------
所需的结果表:
ID | IPaddress | Port | Value
----|---------------|-------|-----------------------------------------------------------
1 | xx.yy.14.15 | 332 | This is good and I can work
--------------------------------------------------------------------------------------
2 | xx.yy.12.12 | 400 | Looks ok and can I work and Yes, please
---------------------------------------------------------------------------------------
3 | xx.yy.14.16 | 401 | How is this and Looks ok and can I work and Yes, please
---------------------------------------------------------------------------------------
这是我尝试过的:
DECLARE @VAR1 VARCHAR(50)
DECLARE @VAR2 VARCHAR(50)
SELECT @VAR1 = T1.VALUE,@VAR2=T2.VALUE
FROM TABLE1 AS T1 INNER JOIN TABLE1 AS T2 ON T1.ID =T2.ID
WHERE T1.IPADDRESS =T2.IPADDRESS
SELECT IPADDRSS,PORT,@VAR1 + ' AND ' +@VAR2 FROM
SELECT T1.*,
ROW_NUMBER() OVER (PARTITION BY T1.IPADDRESS,T1.PORT ORDER BY VALUE) AS NM
FROM TABLE1 AS T1
)TBL
WHERE NM = 1
但是,从上面的查询中,如果只有2个重复的行,我能够实现所需的输出(注意:这里我将IPADDRESS和PORT视为重复,而其他列不重复)
但是,当有3或4或5行有相同的IPADDRESS和PORT时,如何实现我想要的结果?请注意,具有相同IPADDRESS和PORT的行数是动态的,有时可能会超过10。那么,如何在获得理想结果的同时处理这种动态情况呢?
希望我能正确解释。请帮忙。谢谢
刚刚看到你的评论:SQL 2017.Iuga在前面说过,我一直在研究让我感到悲伤的老派聚合技术。 SQL 2017给了我们一个早就应该使用的string_agg函数,这使得它很容易:
SELECT
row_number() over (order by IPaddress, Port) ID
,IPaddress
,Port
,string_agg(Value, ' and ')
from Table1
group by
IPaddress
,Port
如果排序很关键,你可能需要稍微捅一下。
@ KeithL的版本也有用,有点调试......我看到你刚刚解决了。我,我只是不太喜欢XML,这就是为什么我正在研究替代品。
这是创建分隔列表的答案(通常是逗号,但在您的情况下'和'分隔)
尝试在该列中使用一些东西
select rownumber() over (order by IPAddress,Port),IPAddress,Port
,stuff((select ' and ' + value
from table t2
where t1.IPaddress=t2.ipaddress and t1.port=t2.port
order by ID
for XML path(''), type
).value('.','nvarchar(max)')
,1,len(' and '),'') as verbage
from table t1
group by IPAddress,Port
这种方式的工作方式:
外部查询基本上可以在IPAddress,Port上获得分组结果
相关子查询提供与IPAddress,Port关联的每一行的分隔列表
东西逻辑是删除第一个'和'
你可以试试这个:
select t.* from (
select ROW_NUMBER() over (partition by port order by port) rn,id,port,value=stuff (
( select ' ' + value from @t t
where t.port=t1.port
for xml path ('')),1,1,''
) from @t t1
group by id,port
) t
where rn=1