我需要使用网站上的用户选择来打开应用程序屏幕,当用户选择一个项目时,应该在移动应用程序中打开相关页面。但是,应该将网站加载到同一APP的webview中。在这里,我使用Firebase动态链接来管理此导航。
我可以通过模拟器中的chrome浏览器打开网站,并根据需要打开导航到确切页面的App。但是,当我在应用程序内的Web视图中单击相同的组件时,它会引发以下错误,并且应用程序不会打开Firebase动态链接应打开的页面,就像在第一种chrome浏览器中一样。
Can't open url: intent://example.page.link/getapp#Intent;package=com.google.android.gms;action=com.google.firebase.dynamiclinks.VIEW_DYNAMIC_LINK;scheme=https;S.browser_fallback_url=https://play.google.com/store/apps/details%3Fid%3Dcom.ubercab;end;
我的实现如下,
WebApp
App.js
function App() {
return (
<div>
<Button variant="primary">
Open this in your App
</Button>
<Banner url={"https://testingapp.page.link/getapp"}/>
<Banner url={"https://testingapp.page.link/getapp"}/>
<Banner url={"https://testingapp.page.link/getapp"}/>
<Banner url={"https://testingapp.page.link/getapp"}/>
</div>
);
}
Banner.js
const Banner=(props)=>{
const classes = useStyles();
const [expanded, setExpanded] = React.useState(false);
const styles = {
cardAction: {
display: 'block',
textAlign: 'initial',
height: '100%'
}
}
return (
<div onClick={() => window.open(props.url, "_blank")}>
<Card className={classes.root}>
<CardMedia
className={classes.media}
image= {banner}
title="Offer"
/>
</Card>
</div>
);
};
export default Banner;
在移动应用程序端:
App.jsx
import React, { useEffect } from 'react';
import { StyleSheet, Text, View, Button } from 'react-native';
import dynamicLinks from '@react-native-firebase/dynamic-links';
import { WebView } from 'react-native-webview';
import { NavigationContainer } from '@react-navigation/native';
import { createStackNavigator } from '@react-navigation/stack';
function DetailsScreen({ navigation }) {
return (
<View style={{ flex: 1, alignItems: 'center', justifyContent: 'center' }}>
<Text>Details Screen</Text>
</View>
);
}
function HomeScreen({ navigation }) {
async function buildLink() {
console.log('building link');
const link = await dynamicLinks().buildLink({
link: 'https://invertase.io',
// domainUriPrefix is created in your firebase console
domainUriPrefix: 'https://testingapp.page.link',
// optional set up which updates firebase analytics campaign
// "banner". This also needs setting up before hand
analytics: {
campaign: 'banner',
},
});
return link;
}
const handleDynamicLink = link => {
// Handle dynamic link inside your own application
console.log('Received URfffL:' + link.url);
if (link.url === 'https://example.com/packageview') {
console.log('hit package view');
navigation.push('packageview');
}
};
useEffect(() => {
const unsubscribe = dynamicLinks().onLink(handleDynamicLink);
// When the is component unmounted, remove the listener
dynamicLinks()
.getInitialLink()
.then(link => {
console.log('Received URL:' + link.url);
if (link.url === 'https://example.com/packageview') {
console.log('hit package view');
navigation.push('packageview');
}
});
return () => unsubscribe();
}, []);
return (
<WebView source={{ uri: 'http://10.0.2.2:3000/' }}/>
);
}
export default function App() {
const Stack = createStackNavigator();
return (
<NavigationContainer>
<Stack.Navigator>
<Stack.Screen name="Home" component={HomeScreen} />
<Stack.Screen name="packageview" component={DetailsScreen} />
</Stack.Navigator>
</NavigationContainer>
);
}
const styles = StyleSheet.create({
container: {
flex: 1,
backgroundColor: '#fff',
alignItems: 'center',
justifyContent: 'center',
},
});
有人在与此相关的任何事情上有经验吗?关于这里出了什么问题?
[有一个解决方案,但更像是一种变通方法,因此webview似乎用“ intent://”头阻止了请求,因为可以将解决方案“ intent://”添加到WebView的白名单中。检查下面的代码,
<WebView
originWhitelist={['intent://']}
source={{ uri: 'http://10.0.2.2:3000/' }}/>
但是用户体验可能不会那么好,因为这使得可以从Web浏览器打开URL,并且Web浏览器将对应用程序内的页面进行导航。