PRAW：您如何获得提交链接？

Question

def self_post():
for i in sub_reddit:

    reddit.subreddit(i).submit(post_title, url=post_body)
    print("posted on " + i)
    print(submission.permalink)
    submission.reply('This is a test reply')
    print(submission.permalink)

发布主题工作正常，但是我正在尝试获取发布URL，然后回复该提交，我该怎么做？

Answer 1

submit方法返回已创建的提交。因此，您可以通过执行]来保存它

submission = reddit.subreddit(subreddit).submit(post_title, selftext=post_body)
您还可以通过保存调用该方法的结果来获得通过reply创建的注释：

comment = submission.reply('This is a test reply')
然后您的功能将变为：

def self_post(post_title, post_body):
    for subreddit in sub_reddit:
        submission = reddit.subreddit(subreddit).submit(post_title, url=post_body)
        print("posted on " + subreddit)
        print(submission.permalink)
        reply = submission.reply('This is a test reply')
        print(reply.permalink)