我正在根据“日期工作日”绘制我的锻炼重量。我想连接所有符合条件的点:
weights = ([1471.5, 4026. , 2399.5, 5462. , 0. , 2758.1, 6229. , 5132. ])
dates = ['16 Thu', '20 Mon', '21 Tue', '22 Wed', '23 Thu', '24 Fri','25 Sat','27 Mon']
any(x in dates[i] for x in ["Mon","Thu"])
我看到这个问题绘制连接点的线但这解决了每两个点,但我的问题是我可能会跳过几天。我希望代码是健壮的。
我将其用于上述“日期”和“重量”:
plt.pyplot.plot(dates,weights,'ro-')
plt.pyplot.xticks(dates)
plt.pyplot.grid(b=True, which='major', color='#666666', linestyle='-')
plt.pyplot.yticks(weights)
plt.pyplot.show()
这产生了这个不连贯的情节:
我想要这个输出:
所以我这样做了:
MonThudate = []
TueFridate = []
WedSatdate = []
MonThuwt = []
TueFriwt = []
WedSatwt = []
for i in range(len(dates)):
if any(x in dates[i] for x in ["Mon","Thu"]):
MonThudate.append(dates[i])
MonThuwt.append(weights[i])
if any(x in dates[i] for x in ["Tue","Fri"]):
TueFridate.append(dates[i])
TueFriwt.append(weights[i])
if any(x in dates[i] for x in ["Wed","Sat"]):
WedSatdate.append(dates[i])
WedSatwt.append(weights[i])
#MonThuDate = ['16 Thu', '20 Mon', '23 Thu', '27 Mon']
#MonThuwt = [1471.5, 4026.0, 0.0, 5132.0]
plt.pyplot.plot(MonThudate,MonThuwt,'ro-')
plt.pyplot.plot(WedSatdate,WedSatwt,'ro-')
plt.pyplot.plot(TueFridate,TueFriwt,'ro-')
它产生了这个:
但是这里,整个图表的 x 轴并不相同。这是脱节的。
所以基本上您只想连接一周中的某些天。然后,您需要使用正确的组标签来标记这些日期,并在每个组上绘制:
# create day group:
day_groups = [['Thu','Mon'], ['Tue','Fri'], ['Wed', 'Sat'],['Sun']]
day_dict = {day:i for i,groups in enumerate(day_groups) for day in groups}
# {'Thu': 0, 'Mon': 0, 'Tue': 1, 'Fri': 1, 'Wed': 2, 'Sat': 2, 'Sun': 3}
# label the days in the given data set:
# if df.dates is datetime, we can do df.dates.dt.day_name().str[:3]
day_labels = df.dates.str.split(expand=True)[1].map(day_dict)
# groupby and plot:
fig, ax = plt.subplots(figsize=(10,6))
df.weights.groupby(day_labels).plot(ax=ax, marker='o')
ax.set_xticklabels([0] + df.dates.tolist())
ax.grid(b=True, which='major', color='#666666', linestyle='-')
plt.show()
输出:
注意:建议您将
df.dates
转换为datetime
,以便自动排列x轴。