我需要在 BigQuery 上的 GA4 的同一会话期间触发的两个不同事件的事件参数

Question

1. 以下查询提取我需要的事件

   purchase

   的事件参数：

   SELECT
      event_date,
      event_name,
      traffic_source.medium,
      traffic_source.source,
      (
      SELECT
        value.string_value
      FROM
        UNNEST (event_params)
      WHERE
        KEY= 'form_id') AS form_id,
      (
      SELECT
        value.int_value
      FROM
        UNNEST(event_params)
      WHERE
        KEY = 'ga_session_id') AS session_id,
    FROM
      `table1`
    WHERE
      event_name = 'purchase'
   

2. 这个其他查询取消了自定义事件的事件参数的嵌套，我需要将其与上面的

   purchase

   事件的寄存器连接起来：

   SELECT
      event_date,
      event_name,
      (
      SELECT
        value.int_value
      FROM
        UNNEST(event_params)
      WHERE
        KEY = 'ga_session_id') AS session_id,
      (
      SELECT
        value.string_value
      FROM
        UNNEST(event_params)
      WHERE
        KEY = 'campaign_id') AS experiment_id,
      (
      SELECT
        value.string_value
      FROM
        UNNEST(event_params)
      WHERE
        KEY = 'campaing_name') AS experiment_name,
      (
      SELECT
        value.string_value
      FROM
        UNNEST(event_params)
      WHERE
        KEY = 'variation_name') AS variantion_name 
        #COUNT(1) AS sessions
    FROM
      `table1`
    WHERE
      event_name ="kameleoon_experiment"
   

3. 我们在两个查询中都有 event.key 的共同值

   ga_session_id

将相同“ga_session_id”的购买事件参数和自定义事件的事件参数加入同一行的查询是什么？

我目前正在单独下载查询结果，然后使用

ga_session_id

作为键来查找两个表。

Answer 1

这取决于这两个事件之间是什么样的关系。 如果没有（不牢固）依赖关系，并且您只想将它们显示在一行中，那么您可以使用完全连接。

这应该看起来像：

WITH
  purchase AS (
  SELECT
    event_date,
    event_name,
    traffic_source.medium,
    traffic_source.source,
    (
    SELECT
      value.string_value
    FROM
      UNNEST (event_params)
    WHERE
      KEY= 'form_id') AS form_id,
    (
    SELECT
      value.int_value
    FROM
      UNNEST(event_params)
    WHERE
      KEY = 'ga_session_id') AS session_id,
  FROM
    `analytics_.events_*` gae --
  WHERE
    gae.event_name = "purchase"
)
,kameleoon_experiment AS (
  SELECT
    event_date,
    event_name,
    (
    SELECT
      value.int_value
    FROM
      UNNEST(event_params)
    WHERE
      KEY = 'ga_session_id') AS session_id,
    (
    SELECT
      value.string_value
    FROM
      UNNEST(event_params)
    WHERE
      KEY = 'campaign_id') AS experiment_id,
    (
    SELECT
      value.string_value
    FROM
      UNNEST(event_params)
    WHERE
      KEY = 'campaing_name') AS experiment_name,
    (
    SELECT
      value.string_value
    FROM
      UNNEST(event_params)
    WHERE
      KEY = 'variation_name') AS variantion_name
  FROM
    `analytics_.events_*` gae --
  WHERE
    gae.event_name = "kameleoon_experiment"
)
-- Join two tables in one row
SELECT
  pur.event_date,
  pur.event_name,
  pur.medium,
  pur.source,
  pur.form_id,
  pur.session_id,
  --kam.event_date,
  --kam.event_name,
  --kam.session_id,
  kam.experiment_id,
  kam.experiment_name,
  kam.variantion_name
FROM
  purchase pur
FULL JOIN
  kameleoon_experiment kam
ON pur.event_date = kam.event_date
  AND pur.session_id = kam.session_id ;

但通常，这两者之间存在某种关系（例如购买总是被触发，kameleoon_experiment 仅基于特定条件之后触发）。 在这种情况下，您应该使用“LEFT JOIN”或“INNER JOIN”来代替。

您可以查看有关此问题的一些帖子，即：https://www.geeksforgeeks.org/sql-join-set-1-inner-left-right-and-full-joins/