将参数传递给实例继承的方法

Question

该代码的目标是使用继承方法print的构造函数和允许呈现Biz信息的构造函数，基于该方法，再加上一些额外的内容[size），创建一个简单的biz（业务）配置文件。 。预期的输出是“ Hexis的核心是技术”2。相反，我得到的是“ undefined的核心是undefined” 2。

如何在继承的bizOneHexis方法中将PrintBizInfo的第一个参数（this的实例）作为print的参数传递？

const bizDataBase = [
  {name: "Hexis", core: "tech"},
  {name: "Lexia", core: "consulting"}
  ]

function PrintBizCore (print){
  this.print = function (){
    //I want to pass bizDataBase[0] as the context of this.name etc.
    console.log(`The core of ${this.name} is ${this.core}` );
  }
  this.print();
}

function PrintBizInfo (print, size){
  PrintBizCore.call(this, print);
  this.size = 'Its size is ' + size;
}

let bizOneHexis = new PrintBizInfo (bizDataBase[0], 2); //-> The core of undefined is undefined
console.log(bizOneHexis.size); //-> "Its size is 2"

我得到了如下修改代码的预期结果：

const bizDataBase = [
  {name: "Hexis", core: "tech"},
  {name: "Lexia", core: "consulting"}
  ]

function PrintBizCore (print){
  this.print = function (){
    console.log(`The core of ${bizDataBase[0].name} is ${bizDataBase[0].core}` );
  }
  this.print();
}

function PrintBizInfo (print, size){
  PrintBizCore.call(this, print);
  this.size = 'Its size is ' + size;
}

let bizOneHexis = new PrintBizInfo (bizDataBase[0], 2); //-> "The core of Hexis is tech"
console.log(bizOneHexis.size); //-> "Its size is 2"

Answer 1

我重构了上面的代码。它没有回答我的一些问题，但是解决了如何获得所需的输出（我认为这对于从事类似于彭博社服务项目的程序员来说有点有趣。无论如何：

function PrintBizCore (print){
  this.print = function (){
    console.log(`The core of ${this.name} is ${this.core}` );
  }
  this.print();
}

const bizDataBase = [
  {name: "Hexis", core: "tech"}, {name: "Lexia", core: "consulting"}
  ];

function printer (obj){
  obj.forEach(function(brand){
    return PrintBizCore.call(brand)
  })
}

printer(bizDataBase);
//-> "The core of Hexis is tech"
//-> "The core of Lexia is consulting"