如何将Dictionary作为参数发送至Get请求Swift。

问题描述 投票:0回答:1

我必须调用GET API,比如

需要。

http://ctesterst.net/api/Customers/homeData?lat=12.456&lng=76.786&current_app_version=123&current_device=%7B%22Test%22%3A%22123%22%2C%22name%22%3A%22something%22%2C%22tested%22%3Atrue%7D&access_token=Km3R2AbU0yzAcVkp9BCxmCmaoC5k20fBiQxfLhIBIAolwJGgYw5w5E8X0NZzlDh8

像这样的我都要调用。

输入参数怎么加?

我是这样做的。

我的json字符串是:请求模型

 struct RequestData: Codable {
                struct Devices: Codable {
                    let test: String
                    let name: String
                    let tested:Bool
                }
                let   current_device: Devices

            }

和我的网址是:

urlAppend = val + "&lat=\(lati)" + "&lng=\(long)" + "&current_app_version=\(appVersion)" + "&current_device=\(jsonString)"

它越来越崩溃......请给我解决方案。

请给我解决方案。

ios json swift iphone swift4
1个回答
1
投票

你可以使用URLComponents来实现,URLComponents是在Foundation中定义的。

        var components = URLComponents()

        components.scheme = "http"
        components.host = "ctesterst.net"
        components.path = "/api/Customers/homeData"

        let queryItemLat = URLQueryItem(name: "lat", value: "12.456")
        let queryItemLong = URLQueryItem(name: "lng", value: "76.786")
        let queryItemAppVersion = URLQueryItem(name: "current_app_version", value: "123")
        let queryItemDevice = URLQueryItem(name: "current_device", value: "something")
        let queryItemToken = URLQueryItem(name: "access_token", value: "Km3R2AbU0yzAcVkp9BCxmCmaoC5k20fBiQxfLhIBIAolwJGgYw5w5E8X0NZzlDh8")

        components.queryItems = [queryItemLat, queryItemLong,queryItemAppVersion,queryItemDevice,queryItemToken]
        print(components.url)
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