如何使用setTimeout函数更改v-img源

问题描述 投票:-1回答:1

我的代码有问题:

<v-card class="d-flex flex-column">
<v-img id="image" src="w3schools.com/js/landscape.jpg" height="600"> <v-card-title class="headline"> 
Search for 
<v-spacer></v-spacer> 
<span class="caption font-italic font-weight-light">yes</span> 
</v-card-title> 
</v-img> 
</v-card> 

<script> 
setTimeout(function() { document.getElementById("image").setAttribute("src", "w3schools.com/js/smiley.gif"); }, 5000); </script>

它没有改变图像。似乎是什么问题?

javascript html vue.js vuetify.js
1个回答
0
投票

不建议您在操作DOM时尝试尝试创建一个名为url的数据属性,并在所需的位置进行更改,例如,按如下所示在创建的挂钩中设置setTimeout

new Vue({
  el: '#app',
  vuetify: new Vuetify(),
  data() {
    return {
      url: 'https://www.w3schools.com/js/landscape.jpg',
    }
  },
  created(){
   setTimeout(()=>{
   this.url="https://www.w3schools.com/js/smiley.gif"},5000)
  }
})
<link href="https://fonts.googleapis.com/css?family=Roboto:100,300,400,500,700,900" rel="stylesheet">
<link href="https://cdn.jsdelivr.net/npm/@mdi/[email protected]/css/materialdesignicons.min.css" rel="stylesheet">
<link href="https://cdn.jsdelivr.net/npm/[email protected]/dist/vuetify.min.css" rel="stylesheet">
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1, user-scalable=no, minimal-ui">
<script src="https://cdn.jsdelivr.net/npm/[email protected]/dist/vue.js"></script>
<script src="https://cdn.jsdelivr.net/npm/[email protected]/dist/vuetify.js"></script>

<div id="app">
  <v-app>
    <v-content>
      <v-container>
      <v-card class="d-flex flex-column"> <v-img id="image" :src="url" height="600"> <v-card-title class="headline"> Search for <v-spacer></v-spacer> <span class="caption font-italic font-weight-light">yes</span> </v-card-title> </v-img> </v-card>
      </v-container>
    </v-content>
  </v-app>
</div>
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