在 Python 中将类的实例传递给多进程

Question

   import multiprocessing
   import time

   def sleeper(sec):
   time.sleep(sec)

   if __name__ == "__main__":  
     sec=1
     process = multiprocessing.Process(target=sleeper,args=[sec])
     process.start()

---

上面的代码运行良好。但是，如果 sleeper 函数是类实例中的方法，则该方法不起作用。所以我需要一些想法，如果 sleeper 函数是即时方法我应该做什么（如下所示）

    class SleepingClass:
      def __init__(self, sec):
        self.sec = sec

      def sleeper(sec):
      time.sleep(sec) 

sleepingClass = SleepingClass(1)


if __name__ == "__main__":  
    sec=1
    process = multiprocessing.Process(target=sleepingClass.sleeper,args=[sec])
    process.start()

我尝试运行不在实例类中的方法并且它有效。但当我把它放在实例类中时，它却没有。

Answer 1

课程写得不正确。代码中的评论如下：

import multiprocessing
import time

class SleepingClass:
    def __init__(self, sec):
        self.sec = sec

    def sleeper(self):  # No need for argument.  Instance has it.
        print(f'sleeping for {self.sec} seconds...')
        time.sleep(self.sec) 

if __name__ == "__main__":
    # Create the instance only in main
    sleepingClass = SleepingClass(1)
    # Pass it to the sub-process...no need to pass an argument.
    process = multiprocessing.Process(target=sleepingClass.sleeper)
    process.start()