grails spring security rest status 401重定向到控制器的操作以抛出自定义错误消息

问题描述 投票:4回答:1

我们正在使用spring-security-core:2.0-RC4spring-security-rest:1.4.0 plugin和grails 2.4.2。他们俩都工作正常。当用户输入无效凭证时,spring-security-rest:1.4.0插件会给出401,它在Config.groovy中配置

grails.plugin.springsecurity.rest.login.failureStatusCode =  401

这是控制台输出的小片段

rest.RestAuthenticationFilter  - Actual URI is /api/login; endpoint URL is /api/login
rest.RestAuthenticationFilter  - Applying authentication filter to this request
credentials.DefaultJsonPayloadCredentialsExtractor  - Extracted credentials from JSON payload. Username: [email protected], password: [PROTECTED]
rest.RestAuthenticationFilter  - Trying to authenticate the request
authentication.ProviderManager  - Authentication attempt using org.springframework.security.authentication.dao.DaoAuthenticationProvider
dao.DaoAuthenticationProvider  - User '[email protected]' not found
rest.RestAuthenticationFilter  - Authentication failed: Bad credentials
rest.RestAuthenticationFailureHandler  - Setting status code to 401
context.HttpSessionSecurityContextRepository  - SecurityContext is empty or contents are anonymous - context will not be stored in HttpSession.
context.SecurityContextPersistenceFilter  - SecurityContextHolder now cleared, as request processing completed

现在没有错误消息或响应,只是状态401被发送到客户端。现在我尝试在401状态时发送错误响应。

在UrlMappings.groovy中添加了以下行

"401"(controller:'unauthorized',action:'sendErrorResponse')

创建了UnauthorizedController.groovy并添加了sendErrorResponse(),如下所示

def sendErrorResponse() { 
        try{
            int errorCode = grailsApplication.config.customExceptions.account.fourZeroOne.loginNotAuthorized.errorCode
            int status = grailsApplication.config.customExceptions.account.fourZeroOne.loginNotAuthorized.status
            String message = grailsApplication.config.customExceptions.account.fourZeroOne.loginNotAuthorized.message
            String extendedMessage = grailsApplication.config.customExceptions.account.fourZeroOne.loginNotAuthorized.extendedMessage
            String moreInfo = grailsApplication.config.customExceptions.account.fourZeroOne.loginNotAuthorized.moreInfo

            throw new AccountException(status,errorCode,message,extendedMessage,moreInfo)
        }catch(AccountException e){
            log.error e.errorResponse()
            response.setStatus(e.errorResponse().status)
            render e.errorResponse()
        }
    }

我的想法是在401上将调用控制器并且该方法将呈现错误响应,但它不起作用。

我的方法对吗?

实现这个的任何其他最佳实践或想法?

任何指向正确方向的人都会受到赞赏。

万分感谢。

json rest grails spring-security grails-plugin
1个回答
0
投票

您需要使用自己的自定义版本覆盖grails.plugin.springsecurity.rest.RestAuthenticationFailureHandler bean。

它可以是这样的:

@Slf4j
@CompileStatic
class CustomRestAuthenticationFailureHandler implements AuthenticationFailureHandler {

    /**
     * Configurable status code, by default: conf.rest.login.failureStatusCode?:HttpServletResponse.SC_FORBIDDEN
     */
    Integer statusCode

    MessageSource messageSource

    /**
     * Called when an authentication attempt fails.
     * @param request the request during which the authentication attempt occurred.
     * @param response the response.
     * @param exception the exception which was thrown to reject the authentication request.
     */
    void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response, AuthenticationException exception) throws IOException, ServletException {
        response.setStatus(statusCode)
        response.addHeader('WWW-Authenticate', Holders.config.get("grails.plugin.springsecurity.rest.token.validation.headerName").toString())
    def errorMessage
    if (exception instanceof AccountExpiredException) {
        errorMessage = messageSource.getMessage("springSecurity.errors.login.expired", null as Object[], LocaleContextHolder.getLocale())
    } else if (exception instanceof CredentialsExpiredException) {
        errorMessage = messageSource.getMessage("springSecurity.errors.login.passwordExpired", null as Object[], LocaleContextHolder.getLocale())
    } else if (exception instanceof DisabledException) {
        errorMessage = messageSource.getMessage("springSecurity.errors.login.disabled", null as Object[], LocaleContextHolder.getLocale())
    } else if (exception instanceof LockedException) {
        errorMessage = messageSource.getMessage("springSecurity.errors.login.locked", null as Object[], LocaleContextHolder.getLocale())
    } else {
        errorMessage = messageSource.getMessage("springSecurity.errors.login.fail", null as Object[], LocaleContextHolder.getLocale())
    }
    PrintWriter out = response.getWriter()
    response.setContentType("aplication/json")
    response.setCharacterEncoding("UTF-8");
    out.print(new JsonBuilder([message: errorMessage]).toString());
    out.flush();
    }
}

在你的resources.groovy你应该有

restAuthenticationFailureHandler(CustomRestAuthenticationFailureHandler) {
    statusCode = HttpServletResponse.SC_UNAUTHORIZED
    messageSource = ref("messageSource")
}
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