Python写函数输出到文件

问题描述 投票:2回答:4

如果这是一个愚蠢的问题,我很抱歉,但我没有太多的Python经验

我有比较文件的功能

def compare_files(file1, file2):
    fname1 = file1
    fname2 = file2

    # Open file for reading in text mode (default mode)
    f1 = open(fname1)
    f2 = open(fname2)
    # Print confirmation
    #print("-----------------------------------")
    #print("Comparing files ", " > " + fname1, " < " +fname2, sep='\n')
    #print("-----------------------------------")

    # Read the first line from the files
    f1_line = f1.readline()
    f2_line = f2.readline()

    # Initialize counter for line number
    line_no = 1

    # Loop if either file1 or file2 has not reached EOF

    while f1_line != '' or f2_line != '':

       # Strip the leading whitespaces
      f1_line = f1_line.rstrip()
      f2_line = f2_line.rstrip()

      # Compare the lines from both file
      if f1_line != f2_line:

         ########## If a line does not exist on file2 then mark the output with + sign
        if f2_line == '' and f1_line != '':
            print ("Line added:Line-%d" % line_no + "-"+ f1_line)
         #otherwise output the line on file1 and mark it with > sign
        elif f1_line != '':
            print ("Line changed:Line-%d" % line_no + "-"+ f1_line)


        ########### If a line does not exist on file1 then mark the output with + sign
        if f1_line == '' and f2_line != '':
            print ("Line removed:Line-%d" % line_no + "-"+ f1_line)
          # otherwise output the line on file2 and mark it with < sign
         #elif f2_line != '':
            #print("<", "Line-%d" %  line_no, f2_line)

         # Print a blank line
         #print()

    #Read the next line from the file
      f1_line = f1.readline()
      f2_line = f2.readline()
      #Increment line counter
      line_no += 1

    # Close the files
    f1.close()
    f2.close()

我想将函数输出打印到文本文件

result=compare_files("1.txt", "2.txt")

print (result)
Line changed:Line-1-aaaaa
Line added:Line-2-sss
None

我试过以下:

f = open('changes.txt', 'w')

f.write(str(result))

f.close

但只有None打印到changes.txt

我正在使用“workaround”sys.stdout,但是想知道是否有其他方法而不是重定向打印输出。

如果在函数输出中我指定return而不是print,那么我只得到第一个输出行(Line changed:Line-1-aaaaa)到changes.txt

python string-comparison
4个回答
0
投票

因为您在默认情况下没有返回任何内容,所以函数会返回None,以便反映在changes.txt文件中。您可以创建一个存储所需输出的变量并将其返回。

def compare_files(file1, file2):
    fname1 = file1
    fname2 = file2

    # Open file for reading in text mode (default mode)
    f1 = open(fname1)
    f2 = open(fname2)

    output_string = ""

    # Print confirmation
    # print("-----------------------------------")
    # print("Comparing files ", " > " + fname1, " < " +fname2, sep='\n')
    # print("-----------------------------------")

    # Read the first line from the files
    f1_line = f1.readline()
    f2_line = f2.readline()

    # Initialize counter for line number
    line_no = 1

    # Loop if either file1 or file2 has not reached EOF

    while f1_line != '' or f2_line != '':

        # Strip the leading whitespaces
        f1_line = f1_line.rstrip()
        f2_line = f2_line.rstrip()

        # Compare the lines from both file
        if f1_line != f2_line:

            ########## If a line does not exist on file2 then mark the output with + sign
            if f2_line == '' and f1_line != '':
                print("Line added:Line-%d" % line_no + "-" + f1_line)
                output_string += "Line added:Line-%d" % line_no + "-" + f1_line + "\n"
            # otherwise output the line on file1 and mark it with > sign
            elif f1_line != '':
                print("Line changed:Line-%d" % line_no + "-" + f1_line)
                output_string += "Line changed:Line-%d" % line_no + "-" + f1_line +"\n"

            ########### If a line does not exist on file1 then mark the output with + sign
            if f1_line == '' and f2_line != '':
                print("Line removed:Line-%d" % line_no + "-" + f1_line)
                output_string += "Line removed:Line-%d" % line_no + "-" + f1_line +"\n"
            # otherwise output the line on file2 and mark it with < sign
            # elif f2_line != '':
        # print("<", "Line-%d" %  line_no, f2_line)

        # Print a blank line
        # print()

        # Read the next line from the file
        f1_line = f1.readline()
        f2_line = f2.readline()
        # Increment line counter
        line_no += 1

    # Close the files
    f1.close()
    f2.close()
    return output_string

1
投票

你的'compare_files'函数不返回任何内容,因此没有任何内容写入文件。使函数“返回”某些东西,它应该工作。


0
投票

你的功能没有返回任何东西,所以你打印'无'。如果你想让所有的print都转到一个文件而不是stdout,就像默认情况下那样,你可以将每个print语句转换为返回值。

或者你可以像在here中那样使用整个程序的重定向。


0
投票

你的compare_files()只是打印,但没有传递任何东西给它的来电者。

如果要将一个项目传递给调用者,请使用return。你的功能流程就此结束。

如果你想将几个项目传递给调用者,你可以使用yield。使用yield将您的功能转换为生成器功能。调用生成器函数会生成一个可以迭代的生成器对象。

例:

def produce_strings():
    for i in ['a', 'b', 'c']:
        yield i + "x"

result = "\n".join(produce_strings())
print(result) # prints a line end separated string made of "ax", "bx" and "cx".
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