我一次只能使用一个中间件。在构造函数中..我想在构造函数或两个中间件中使用if else条件。
我只能在构造函数中使用一个中间件,如果其他条件也不起作用
我只想要一个功能工作或根据中间件使用。我有两个单独的表进行身份验证
Following middleware pointing to diffrent table
$this->middleware('auth:admin') - admins
$this->middleware('auth')- user
示例如下
如果别的
class HRJob extends Controller
{
public function __construct()
{
if(Auth::guard('admin'))
{
$this->middleware('auth:admin');
}
else
{
$this->middleware('auth');
}
}
public function userdetails()
{
dd(Auth::user());
}
}
两个中间件
class HRJob extends Controller
{
public function __construct()
{
$this->middleware('auth:admin');
$this->middleware('auth');
}
public function userdetails()
{
dd(Auth::user());
}
}
您可以在控制器中尝试这样的操作
class UserController extends Controller
{
/**
* Instantiate a new UserController instance.
*
* @return void
*/
public function __construct()
{
$this->middleware('auth');
$this->middleware('log', ['only' => [
'fooAction',
'barAction',
]]);
$this->middleware('subscribed', ['except' => [
'fooAction',
'barAction',
]]);
}
}
您也可以使用中间件组
/**
* The application's route middleware groups.
*
* @var array
*/
protected $middlewareGroups = [
'web' => [
\App\Http\Middleware\EncryptCookies::class,
\Illuminate\Cookie\Middleware\AddQueuedCookiesToResponse::class,
\Illuminate\Session\Middleware\StartSession::class,
\Illuminate\View\Middleware\ShareErrorsFromSession::class,
\App\Http\Middleware\VerifyCsrfToken::class,
],
'api' => [
'throttle:60,1',
'auth:api',
],
];