我在s1
函数中尝试遍历字符串以将每个元素推入字符串类型为isPalindrome()
的堆栈时遇到此错误。
没有重载函数实例“ std :: stack <_ty> :: push[与_Ty = std :: string,_Container = std :: deque>]“与参数列表匹配
当我分配时,位于堆栈顶部的字符串变量弹出错误:
'std :: stack >> :: top':非标准语法;使用“&”创建指向成员的指针
为什么提到std::deque
?
#include <iostream>
#include <string>
#include <stack>
#include <algorithm>
class Palindrome
{
public:
Palindrome();
void inputString();
std::string convert2lower();
bool isPalindrome();
private:
std::string userstring;
std::stack<std::string> s1;
};
Palindrome::Palindrome()
{}
void Palindrome::inputString()
{
std::cout << "Enter a string: ";
std::getline(std::cin,userstring);
}
std::string Palindrome::convert2lower()
{
userstring.erase(remove(userstring.begin(), userstring.end(), ' '), userstring.end());
userstring.erase(std::remove_if(userstring.begin(), userstring.end(), ispunct), userstring.end());
transform(userstring.begin(), userstring.end(), userstring.begin(), tolower);
return userstring;
}
bool Palindrome::isPalindrome()
{
size_t n = userstring.size();
for (size_t i = 0; i < n; ++i)
{
s1.push(userstring[i]);
}
std::string reversed;
for (size_t i = 0; i < n; ++i)
{
std::string temp = s1.top;
reversed.insert(i,temp);
s1.pop();
}
if (reversed == userstring)
{
return true;
}
return false;
}
int main()
{
Palindrome p1;
p1.inputString();
std::cout << "\nCalling convert2lower(): " << std::endl;
std::cout << "The new string is " << p1.convert2lower() << std::endl;
std::cout << "\nCalling isPalindrome(): " << std::endl;
if (!p1.isPalindrome())
{
std::cout << "String is NOT a Palindrome!" << std::endl;
}
else
{
std::cout << "String is a Palindrome!" << std::endl;
}
}
这是您的代码,具有绝对的最小更改...
#include <iostream>
#include <string>
#include <stack>
#include <algorithm>
class Palindrome
{
public:
Palindrome();
void inputString();
std::string convert2lower();
bool isPalindrome();
private:
std::string userstring;
std::stack<char> s1;
};
Palindrome::Palindrome()
{}
void Palindrome::inputString()
{
std::cout << "Enter a string: ";
std::getline(std::cin, userstring);
}
std::string Palindrome::convert2lower()
{
userstring.erase(remove(userstring.begin(), userstring.end(), ' '), userstring.end());
userstring.erase(std::remove_if(userstring.begin(), userstring.end(), ispunct), userstring.end());
transform(userstring.begin(), userstring.end(), userstring.begin(), tolower);
return userstring;
}
bool Palindrome::isPalindrome()
{
size_t n = userstring.size();
for (size_t i = 0; i < n; ++i)
{
s1.push(userstring[i]);
}
std::string reversed;
for (size_t i = 0; i < n; ++i)
{
char temp = s1.top();
reversed.insert(i, &temp, 1);
s1.pop();
}
if (reversed == userstring)
{
return true;
}
return false;
}
int main()
{
Palindrome p1;
p1.inputString();
std::cout << "\nCalling convert2lower(): " << std::endl;
std::cout << "The new string is " << p1.convert2lower() << std::endl;
std::cout << "\nCalling isPalindrome(): " << std::endl;
if (!p1.isPalindrome())
{
std::cout << "String is NOT a Palindrome!" << std::endl;
}
else
{
std::cout << "String is a Palindrome!" << std::endl;
}
}
以下是您的问题的答案: