无法在列表中找到空字符串？

Question

学习用Python编程。我正在尝试使用海龟制作 XOX 游戏。我做了一个函数来检查列表中是否有 X(x) 或 O(y)，如果有的话，我将放置 X 或 O。 该函数运行良好，直到我试图查找列表中是否没有空引号，但我猜它没有像我想象的那样工作。

部分问题出现的地方：

from turtle import *
list1 = [""] * 9

if (
# If there are no empty strings in the list, decide a draw. 
        not list1[0] == ""
        and not list1[1] == ""
        and not list1[2] == ""
        and not list1[3] == ""
        and not list1[4] == ""
        and not list1[5] == ""
        and not list1[6] == ""
        and not list1[7] == ""
        and not list1[8] == ""
    ):
        print("It's a tie.")
        replay()

整体功能：

from turtle import *
list1 = [""] * 9

def goplace(x, y):
    pencolor("blue")
    sq_1 = 0 < x < 1 and 0 < y < 1
    sq_2 = 0 < x < 1 and 1 < y < 2
    sq_3 = 0 < x < 1 and 2 < y < 3
    sq_4 = 1 < x < 2 and 0 < y < 1
    sq_5 = 1 < x < 2 and 1 < y < 2
    sq_6 = 1 < x < 2 and 2 < y < 3
    sq_7 = 2 < x < 3 and 0 < y < 1
    sq_8 = 2 < x < 3 and 1 < y < 2
    sq_9 = 2 < x < 3 and 2 < y < 3
    count_x = 0
    count_y = 0
    for item_x in list1:
        if item_x == "x":
            count_x += 1
    for item_y in list1:
        if item_y == "y":
            count_y += 1
    if count_x <= count_y:
        if sq_1:
            if list1[0] == "":
                list1[0] = "x"
                print(list1)
                draw_x(0, 0)
            else:
                return
        elif sq_2:
            if list1[1] == "":
                list1[1] = "x"
                print(list1)
                draw_x(0, 1)
            else:
                return
        elif sq_3:
            if list1[2] == "":
                list1[2] = "x"
                print(list1)
                draw_x(0, 2)
            else:
                return
        elif sq_4:
            if list1[3] == "":
                list1[3] = "x"
                print(list1)
                draw_x(1, 0)
            else:
                return
        elif sq_5:
            if list1[4] == "":
                list1[4] = "x"
                print(list1)
                draw_x(1, 1)
            else:
                return
        elif sq_6:
            if list1[5] == "":
                list1[5] = "x"
                print(list1)
                draw_x(1, 2)
            else:
                return
        elif sq_7:
            if list1[6] == "":
                list1[6] = "x"
                print(list1)
                draw_x(2, 0)
            else:
                return
        elif sq_8:
            if list1[7] == "":
                list1[7] = "x"
                print(list1)
                draw_x(2, 1)
            else:
                return
        elif sq_9:
            if list1[8] == "":
                list1[8] = "x"
                print(list1)
                draw_x(2, 2)
            else:
                return
    if not (
        list1[0] == list1[1] == list1[2] == "x"
        or list1[3] == list1[4] == list1[5] == "x"
        or list1[6] == list1[7] == list1[8] == "x"
        or list1[0] == list1[4] == list1[8] == "x"
        or list1[2] == list1[4] == list1[6] == "x"
        or list1[0] == list1[1] == list1[2] == "y"
        or list1[3] == list1[4] == list1[5] == "y"
        or list1[6] == list1[7] == list1[8] == "y"
        or list1[0] == list1[4] == list1[8] == "y"
        or list1[2] == list1[4] == list1[6] == "y"
    ):
        r_place()

    if list1[0] == list1[1] == list1[2] == "x":
        print("Player won!")
        replay()
    elif list1[3] == list1[4] == list1[5] == "x":
        print("Player won!")
        replay()
    elif list1[6] == list1[7] == list1[8] == "x":
        print("Player won!")
        replay()
    elif list1[0] == list1[1] == list1[2] == "y":
        print("Computer won!")
        replay()
    elif list1[3] == list1[4] == list1[5] == "y":
        print("Computer won!")
        replay()
    elif list1[6] == list1[7] == list1[8] == "y":
        print("Computer won!")
        replay()
    elif list1[0] == list1[4] == list1[8] == "y":
        print("Computer won!")
        replay()
    elif list1[2] == list1[4] == list1[6] == "y":
        print("Computer won!")
        replay()
    elif list1[0] == list1[4] == list1[8] == "x":
        print("Player won!")
        replay()
    elif list1[2] == list1[4] == list1[6] == "x":
        print("Player won!")
        replay()
    if (
        not list1[0] == ""
        and not list1[1] == ""
        and not list1[2] == ""
        and not list1[3] == ""
        and not list1[4] == ""
        and not list1[5] == ""
        and not list1[6] == ""
        and not list1[7] == ""
        and not list1[8] == ""
    ):
        print("It's a tie.")
        replay()

我尝试使用“！=”，“and”，“not，in，“None”，“''”而不是==“”并尝试仅list1 []，但它们都不适合我。

Answer 1

您需要使用

!=

来测试列表项与空字符串的相等性

""

如：

list1 = ["a"] * 9

# If there are no empty strings in the list, decide a draw. 
if (
    list1[0] != ""
    and list1[1] != ""
    and list1[2] != ""
    and list1[3] != ""
    and list1[4] != ""
    and list1[5] != ""
    and list1[6] != ""
    and list1[7] != ""
    and list1[8] != ""
    ):
  print("Replay!")