pymysql.connect 引发“TypeError：__init__() 采用 1 个位置参数，但给出了 5 个”

Question

这是我建立数据库连接的Python代码。但我的代码中出现类型错误。有什么问题吗？

import pymysql

connnection = pymysql.connect("localhost", "root", "", "dbname")

错误：

Traceback(most recent call last):
 File "c:/Users/Dell/Desktop/Full Code/COllectUrls.py", line 21, in <module>
   connnection = pymysql.connect("localhost", "root", "", "dbname")
TypeError: __init__() takes 1 positional argument but 5 were given

Answer 1

这样就解决了问题。

import pymysql

# Connect to the database
connection = pymysql.connect(host='localhost',
                             user='user',
                             password='passwd',
                             database='db',
                             charset='utf8mb4',
                             cursorclass=pymysql.cursors.DictCursor)

Answer 2

这适用于 3.x 版本。

import pymysql

connection = pymysql.connect(host='localhost', user='root', password='', database='db_emp', charset='utf8mb4', cursorclass=pymysql.cursors.DictCursor)

cursor = connection.cursor()
cursor.execute("SELECT VERSION()")
data = cursor.fetchone()
print ("Database version : %s " % data)

Answer 3

import pymysql

conn=pymysql.connect(host='localhost',user='root',password='12345678',database='studentdb')

Answer 4

我有同样的问题，并使用了 Ramlakhan Kevat 和 mkrieger1 的答案，它无需最后一个参数即可工作：

import pymysql

# Connect to the database
connection = pymysql.connect(host='localhost',
                             user='user',
                             password='passwd',
                             database='db',
                             charset='utf8mb4')