如何使用休眠模式与现有对象创建复合键对象

问题描述 投票:0回答:1

假设我具有以下数据库架构

CREATE TABLE employee(
    id BIGINT AUTO_INCREMENT PRIMARY KEY,
    name VARCHAR(50) NOT NULL,
    hrid VARCHAR (50)
);
CREATE TABLE territory(
    id BIGINT PRIMARY KEY,
    name varchar (50)
);
CREATE TABLE transcode(
    id BIGINT AUTO_INCREMENT PRIMARY KEY,
    code VARCHAR (10) NOT NULL
);
create table employee_territory_function(
  employee_id BIGINT NOT NULL,
  territory_id BIGINT NOT NULL,
  transcode_id BIGINT NOT NULL,
  PRIMARY KEY (employee_id,territory_id),
  CONSTRAINT employeeref FOREIGN KEY (employee_id) REFERENCES employee (id),
  CONSTRAINT territoryref FOREIGN KEY (territory_id) REFERENCES territory (id) ,
  CONSTRAINT transcoderef FOREIGN KEY (transcode_id) REFERENCES transcode (id)
);

现在我具有以下JPA映射的实体

员工实体

@Entity
public class Employee implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;
    private String name;
    private String hrid;
    @OneToMany(fetch = FetchType.LAZY, mappedBy = "employee", cascade = CascadeType.ALL)
    private Set<EmployeeTerritoryFunction> employeeTerritoryFunctionList = new HashSet<>();
    //getters and setters
}

领土实体:

@Entity
public class Territory implements Serializable {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;
    private String name;

    // getters and setters for all field

}

转码实体:

@Entity
public class Territory implements Serializable {
    @Id
    private long id;
    private String name;
    //getters and setters
}

EmployeeTerritoryFunction实体(组合键表)

@Entity
@IdClass(value = EmployeeTerritoryFunctionPK.class)
public class EmployeeTerritoryFunction implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    @ManyToOne
    private Employee employee;

    @Id
    @ManyToOne
    private Territory territory;

    @ManyToOne
    @JoinColumn(name = "transcode_id", referencedColumnName = "id")
    private Transcode transcode;
    //getters and setters
}

EmployeeTerritoryFunction pk

public class EmployeeTerritoryFunctionPK implements Serializable {
    private static final long serialVersionUID = 1L;

    private Long employee;
    private Long territory;
    //getters and setters, no args constructor, equals and hashcode
}

样品插入下方

Employee employee = this.employeeRepository.findByHrid("111");
        if (employee == null) {
            employee = new Employee();
            employee.setName("Marie");
            employee.setHrid("333");
        }

        Territory territory = new Territory();
        territory.setId(2L);
        territory.setName("T2");

        Territory territory2 = new Territory();
        territory2.setId(3L);
        territory2.setName("T3");


        Transcode transcode = this.transcodeRepository.findByCode("ASC");
        Transcode transcode2 = this.transcodeRepository.findByCode("CC");


        EmployeeTerritoryFunction employeeTerritoryFunction1 = new EmployeeTerritoryFunction();

        employeeTerritoryFunction1.setTranscode(transcode);
        employeeTerritoryFunction1.setTerritory(territory);
        employeeTerritoryFunction1.setEmployee(employee);
        employee.getEmployeeTerritoryFunctionList().add(employeeTerritoryFunction1);

        EmployeeTerritoryFunction employeeTerritoryFunction2 = new EmployeeTerritoryFunction();
        employeeTerritoryFunction2.setTranscode(transcode2);
        employeeTerritoryFunction2.setTerritory(territory2);
        employeeTerritoryFunction2.setEmployee(employee);
        employee.getEmployeeTerritoryFunctionList().add(employeeTerritoryFunction2);

        employeeRepository.save(employee);

当我仅使用新对象运行以上代码时,我没有问题,因为休眠会自动插入员工,地区和employee_territory_function列表,但是当我第一次删除所有现有地区,employee_territory_function并尝试使用现有员工插入时,休眠无法自动插入或更新员工,在区域内employee_territory_function自动插入。错误下方

Caused by: org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.example.demo.Employee.employeeTerritoryFunctionList, could not initialize proxy - no Session

当我将oneToMany获取类型替换为EAGER时,出现以下错误

Caused by: javax.persistence.EntityNotFoundException: Unable to find com.example.demo.Territory with id 3

它似乎休眠了,试图查询Territory表,但是当他这样做时我不这样做,因为我删除了Territory和EmployeeTerritoryFunction表上的所有数据,而只删除了员工现有的数据。

如何修复?

java spring hibernate jpa composite-primary-key
1个回答
0
投票

两个类EmployeeTerritoryFunction和EmployeeTerritoryFunctionPK中的字段都应命名为完全相同,并且具有您没有的相同类型。尝试这样:

@Entity
@IdClass(value = EmployeeTerritoryFunctionPK.class)
public class EmployeeTerritoryFunction implements Serializable {
    @Id
    private Long employeeId;

    @ManyToOne
    private Employee employee;

    @Id
    private Long territoryId;

    @ManyToOne
    private Territory territory;
}

public class EmployeeTerritoryFunctionPK implements Serializable {
    private Long employeeId;
    private Long territoryId;
}
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