Bash脚本检查文件是否在另一个目录（incld子目录）中

Question

我正在尝试编写脚本以将一个目录中的文件与另一个目录（包括子目录）进行比较，并查看它们是否存在。我到目前为止所拥有的是：

#!/bin/sh

# This will compare files in 'dropbox>camera uploads' against pics in local 'pictures' folder.
# If present they are moved to 'duplicate' folder if not to 'not_duplicate' inside dropbox
#
# Mar '20
#
#

DROPBOX_LOC="/home/unencrypted/Dropbox/CameraUploads"
DROPBOX_LOC_DUPLICATE="/home/unencrypted/Dropbox/CameraUploads/duplicate"
DROPBOX_LOC_NOT_DUPLICATE="/home/unencrypted/Dropbox/CameraUploads/not_duplicate"
PICS_LOC="/home/user/Pictures"

for file in $DROPBOX_LOC/*
# NOTE: Use of " " preserves whitespace in single variable!

do
    echo "Checking for: $file"
    #ls -l $file

   if [[ -f "$PICS_LOC/${file##*/}" ]]
        then
        echo "$file is a duplicate"
        # Move to duplicate folder
        continue
     else
        echo "$file is a NOT a duplicate"
        # Move to not duplicate folder
        fi
done
exit 0

但是返回：

Checking for: /home/unencrypted/Dropbox/CameraUploads/2015-11-07 16.58.49.jpg
./delete_dropbox_pics.sh: 22: ./delete_dropbox_pics.sh: [[: not found
/home/unencrypted/Dropbox/CameraUploads/2015-11-07 16.58.49.jpg is a NOT a duplicate

任何人都可以提出修复建议（包括如何搜索子目录）？

Answer 1

为什么不使用diff命令。

diff -r <directory1> <directory2>

-r，-递归递归比较找到的任何子目录