如何在Java中的同一对象内将对象序列化为方法?

问题描述 投票:0回答:1

我已经在Java中创建了一个简单的银行对帐单程序。有一个名为FinancialManager的类,它控制某人的银行对帐单。 FinancialManager类在下面。

import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectOutputStream;
import java.util.Vector;

public class FinancialManager implements Serializable{
    private double balance1;
    private Vector<String> statement1;
    public FinancialManager(){
        balance1=0;
        statement1 = new Vector<String>();
    }
    public void deposit(double value){
        balance1 = balance1+value;
        String st = "Deposit  "+String.valueOf(value);
        statement1.add(st);
    }
    public void withdraw(double value){
        if(value<balance1){
            balance1 = balance1 - value;
            String st = "Withdraw "+String.valueOf(value);
            statement1.add(st);
        }else{
            String st = "Withdraw 0.0";
            statement1.add(st);
        }
    }
    public String balance(){
        return String.valueOf(balance1);
    }
    public void statement(){
        String[] array = statement1.toArray(new String[statement1.size()]);
        for(int i=0;i<array.length;i++){
            System.out.println(array[i]);
        }
    }
}

主要类别如下。

public class Main {
    public static void main(String[] args) {
        FinancialManager fm = new FinancialManager();
        fm.deposit(25.00);
        fm.withdraw(12.00);
        fm.deposit(10.00);
        fm.deposit(5.00);
        fm.withdraw(8.00);
        System.out.println("The current balance is "+fm.balance());
        fm.statement();

    }
}

我需要添加一个名为save的方法,该方法应该能够序列化对象。例如,当我在main方法中使用这种方法时,

fm.save("test.ser");

它应该能够将对象序列化到“ test.ser”文件。我该怎么做?

java file stream serializable
1个回答
2
投票

容易做的是创建一个写入文件的ObjectOutputStream。例如:

    public void save(String fileName) throws IOException {
        Path filePath = Path.of(fileName);
        try (ObjectOutputStream objectOutputStream = new ObjectOutputStream(Files.newOutputStream(filePath))) {
            // write "this" - the current object - to the file
            objectOutputStream.writeObject(this);
        }
    }
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