Swift 中的 UIActivityViewController 在 iPad 上崩溃

Question

我正在游戏中创建共享功能，我有代码，它在 iPhone 上运行良好，但当我在 iPad 上测试它时，当我点击共享按钮时，应用程序崩溃了。我正在使用以下代码作为共享按钮

let textToShare = "Check out this website!"

if let myWebsite = NSURL(string: "http://www.apple.com/") {
   let objectsToShare = [textToShare, myWebsite]
   let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: nil)
   self.view?.window?.rootViewController?.presentViewController(activityVC, animated: true, completion: nil)
}

Answer 1

在 iPad 上运行时，UIActivityViewController 具有非空 popoverPresentationController 属性。那么，请尝试以下。

if let wPPC = activityVC.popoverPresentationController {
    wPPC.sourceView = some view
    //  or
    wPPC.barButtonItem = some bar button item
}
presentViewController( activityVC, animated: true, completion: nil )

Answer 2

以@Satachito的答案为基础：作为

sourceView

，您可以在弹出窗口应指向的位置创建一个（不可见的）

CGRect

，并将箭头设置为该方向：

let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: nil)

if UIDevice.current.userInterfaceIdiom == .pad {
    activityVC.popoverPresentationController?.sourceView = UIApplication.shared.windows.first
    activityVC.popoverPresentationController?.sourceRect = CGRect(x: 0, y: 0, width: 300, height: 350)
    activityVC.popoverPresentationController?.permittedArrowDirections = [.left]
}

UIApplication.shared.windows.first?.rootViewController?.present(activityVC, animated: true, completion: nil)

Answer 3

iPad 中不存在 SheetVC。所以你需要为弹出控制器添加一个源视图

@objc private func shareButtonTapped(_ sender: UIButton) {
        let image = UIImage(named: "image")
        let activityItem: [AnyObject] = [image as AnyObject]
        let activityViewController = UIActivityViewController(
            activityItems: activityItem as [AnyObject],
            applicationActivities: nil
        )
        if let popoverController = activityViewController.popoverPresentationController {
            popoverController.sourceView = sender
            popoverController.sourceRect = sender.bounds
        }
        present(activityViewController, animated: true, completion: nil)
    }

Answer 4

popoverPresentationController

sourceView

需要设置为当前视图。

let activityVC = UIActivityViewController(activityItems: [quoteController.attributedString, view.screenShot()], applicationActivities: [])
    
present(activityVC, animated: true)
activityVC.popoverPresentationController?.sourceView = view

Answer 5

iOS 16 即用示例基于之前的示例，未使用已弃用的

windows

func shareAppIntent() {
    let subject = "Share with Friends"
    let extraText = "https://apps.apple.com/..."
    
    guard let mainWindowScene = UIApplication.shared.connectedScenes
            .compactMap({ $0 as? UIWindowScene })
            .first(where: { $0.activationState == .foregroundActive }),
          let mainWindow = mainWindowScene.windows.first,
          let rootViewController = mainWindow.rootViewController else {
        return
    }
    
    if let url = URL(string: extraText) {
        let activityViewController = UIActivityViewController(activityItems: [subject, url], applicationActivities: nil)
        
        // iPad needs extra context, otherwise it will crash
        if UIDevice.current.userInterfaceIdiom == .pad {
            activityViewController.popoverPresentationController?.sourceView = mainWindow
            activityViewController.popoverPresentationController?.sourceRect = CGRect(x: 0, y: 0, width: 300, height: 350)
            activityViewController.popoverPresentationController?.permittedArrowDirections = [.left]
        }
        
        rootViewController.present(activityViewController, animated: true, completion: nil)
    }
}