如何在不使用UPSopover的情况下获得由Storyboard创建的UIViewController？

Question

我有一个iPad应用程序（XCode 4.6，iOS 6.2，情节提要，ARC），我在其中创建了一个UIViewController（未连接到任何segue）以用于UIPopover。这些是ViewController设置：

<< img src =“ https://image.soinside.com/eyJ1cmwiOiAiaHR0cHM6Ly9pLnN0YWNrLmltZ3VyLmNvbS9MYjZQZC5wbmcifQ==” alt =“在此处输入图像描述”>

<< img src =“ https://image.soinside.com/eyJ1cmwiOiAiaHR0cHM6Ly9pLnN0YWNrLmltZ3VyLmNvbS9iZ0N4ci5wbmcifQ==” alt =“在此处输入图像描述”>

我有应该在UIPopover中显示“ viewForPopover” ViewController的代码。

        UIView *anchor = textField;
    UIViewController *viewControllerForPopover =
    [self.storyboard instantiateViewControllerWithIdentifier:@"viewForPopover"];

    popover = [[UIPopoverController alloc]
               initWithContentViewController:viewControllerForPopover];
    [popover presentPopoverFromRect:anchor.frame
                             inView:anchor.superview
           permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

我的问题是：没有self.storyboard。那么我应该如何到达当前类之外的视图控制器呢？ （当前类是UIView的子视图）

Answer 1

在UIStoryboard上调用此方法：

+ (UIStoryboard *)storyboardWithName:(NSString *)name bundle:(NSBundle *)storyboardBundleOrNil

如果您的视图控制器位于“ MainStoryboard.storyboard”中，则可能像这样：

UIViewController *viewControllerForPopover =
    [[UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil]instantiateViewControllerWithIdentifier:@"viewForPopover"];

Answer 2

快速实用功能：

extension UIViewController {


    func presentMyCtl( pushed: Bool){

        let VC = MyController(nibName: "MyController", bundle: nil)

        if pushed{
            let nc = self.navigationController!
            nc.pushViewController(VC, animated: true)

        }else{
            self.present(VC, animated: true, completion: nil)
        }

    }


    func dismissMyCtl(pushed: Bool){

        if pushed{
            let nc = self.navigationController!
            nc.popViewController(animated: true)
        }else{
            self.dismiss(animated: true, completion: nil)
        }
    }
}

其中MyController.swift为类的swift文件，而MyController.xib是包含UI的文件。