如何修复tkinter TypeError：键必须为str，int，float，bool或None，不是Button？

Question

import json 
from tkinter import *
import os

listai = json.load(open("listai.txt"))
listap = json.load(open("listap.txt"))
dict = {}



def dictAdd(item, value):
     global listai, listap
     print(item) #i did this so i could see where it was getting the error
     print(value)
     if item not in listai:
          dictcreator()
          d = open("dicionario.txt", "w")
          dict[item] = value
          d.write(json.dumps(dict))
          listai.append(item)
          try:
               listap.append(float(value))
          except ValueError:
               listap.append(int(value))
          i = open("listai.txt", "w").write(json.dumps(listai))
          p = open("listap.txt", "w").write(json.dumps(listap))

#dictAdd("cereja", 3.9)



def dictcreator():
     global listai, listap
     for x in range(len(listai)):
          dict[listai[x]] = listap[x]
     d = open("dicionario.txt", "w").write(json.dumps(dict))

#dictcreator()


def Add():
     addtop = Toplevel()
     addtopheight = 300
     addtopwidth = 300
     addentryname = StringVar()
     addentryprice = StringVar()
     xwpos = int(mainwindow.winfo_screenwidth()/2 - addtopwidth/2)
     ywpos = int(mainwindow.winfo_screenheight()/2 - addtopheight/2)
     addtop.geometry(f"{addtopwidth}x{addtopwidth}+{xwpos}+{ywpos}")
     addtop.resizable(height = 0, width = 0)
     addtop.config(bg="lightgrey")
     addmainlabel = Label(addtop, text="Adicionar alimento novo", font="arial, 19", fg="green", bg="lightgrey").grid(pady=10, padx=8, row=0, column=0, columnspan=2)
     addlabeln = Label(addtop, text="Alimento -->", bg="lightgrey", font="arial, 10").grid(row=1, column=0, padx=2, pady=8)
     addentryn = Entry(addtop, bg="lightgrey", textvariable = addentryname).grid(row=1, column=1, padx=2, pady=5)
     addlabelp = Label(addtop, text="Preço-->", bg="lightgrey", font="arial, 10").grid(row=2, column=0, padx=2, pady=8)
     addentryp = Entry(addtop, bg="lightgrey", textvariable = addentryprice).grid(row=2, column=1, padx=2, pady=5)
     addbutton = Button(addtop, text="Adicionar", font="arial, 10", fg="green", relief=GROOVE, bg="lightgrey", command = lambda: dictAdd(str(addentryname.get()), str(addentryprice.get())))
     addbutton.grid(pady= 20, padx=10, row=3, column=0, columnspan=2)
     addtop.mainloop()

我收到错误：当我按下名为“ addbutton”的按钮时，“ TypeError：键必须为str，int，float，bool或None，而不是Button”如果需要，这里是终端的更多输出：

laranja
5.7
Exception in Tkinter callback
Traceback (most recent call last):
  File "C:\Users\Asus\AppData\Local\Programs\Python\Python38-32\lib\tkinter\__init__.py", line 1883, in __call__
return self.func(*args)
  File "c:/Users/Asus/PycharmProjects/lista de compras/lista de compras.py", line 57, in <lambda>
addbutton = Button(addtop, text="Adicionar", font="arial, 10", fg="green", relief=GROOVE, bg="lightgrey", command = lambda: dictAdd(str(addentryname.get()), str(addentryprice.get())))
  File "c:/Users/Asus/PycharmProjects/lista de compras/lista de compras.py", line 16, in dictAdd
dictcreator()
  File "c:/Users/Asus/PycharmProjects/lista de compras/lista de compras.py", line 36, in dictcreator
    d = open("dicionario.txt", "w").write(json.dumps(dict))
  File "C:\Users\Asus\AppData\Local\Programs\Python\Python38-32\lib\json\__init__.py", line 231, in dumps
    return _default_encoder.encode(obj)
  File "C:\Users\Asus\AppData\Local\Programs\Python\Python38-32\lib\json\encoder.py", line 199, in encode
    chunks = self.iterencode(o, _one_shot=True)
  File "C:\Users\Asus\AppData\Local\Programs\Python\Python38-32\lib\json\encoder.py", line 257, in iterencode
    return _iterencode(o, 0)
TypeError: keys must be str, int, float, bool or None, not Button

我想知道是否有人可以告诉我如何解决此错误：D。如果有人向我解释解决此错误的方法，我将非常感激。

为了更好地理解代码，基本上，这是一个添加/删除/添加购物车商品的程序，文件“ listai.txt”是所有食品的数组/列表。文件“ listap.txt”是所有价格的数组/列表。基本上，我所做的就是创建一个名为dictcreator的函数，该函数创建字典（称为“ dicionario.txt”，但该字典是字典，但使用葡萄牙语），例如，从listai.txt获得项目1，从listap.txt获得价格1，聚在一起。

外部文件：

listai：[“ cereja”，“ banana”，“ pera”，“ maca”，“ pessego”]

listap：[“ 1.2”，“ 1.9”，“ 2.3”，“ 3.1”，“ 3.9”]

dicionario：{“ cereja”：1.2，“ banana”：1.9，“ pera”：2.3，“ maca”：3.1，“ pessego”：3.9}]

Answer 1

[在python中，字典键可以是任何可哈希的对象，而在json中，它只能是str, int, float, bool or None。如果需要，请尝试使用dill或pickle保存tkinter对象（不需要）。希望对您有所帮助！