如何用html模板解组结构？

Question

我正在尝试将JSON解组到我的Mail结构，但是Go在解析html_tmpl和text_tmpl字段时返回错误。 我该如何解决这个问题？

HtmlTmpl字段来自：

html, err := template.ParseFiles(pathToHTMLFile)

这是您可以测试的基本示例

package main

import (
    "encoding/json"
    "fmt"
    "html/template"
    "time"
)

type Mail struct {
    Id       string            `json:"id"`
    Subject  string            `json:"subject"`
    From     string            `json:"from"`
    To       string            `json:"to"`
    Date     time.Time         `json:"date"`
    HtmlTmpl template.Template `json:"html_tmpl"`
    TextTmpl template.Template `json:"text_tmpl"`
    Context  map[string]string `json:"context"`
}

func main() {
  mail := &Mail{}
  s := `{"id":"","subject":"Test mail","from":"[email protected]","to":"[email protected]","date":"0001-01-01T00:00:00Z","html_tmpl":{"Tree":{"Name":"template.html","ParseName":"template.html","Root":{"NodeType":11,"Pos":0,"Nodes":[{"NodeType":0,"Pos":0,"Text":"PCFET0NUWVBFIGh0bWw+CjxodG1sIGxhbmc9InJ1Ij4KPGhlYWQ+Cgk8bWV0YSBodHRwLWVxdWl2PSJDb250ZW50LVR5cGUiIGNvbnRlbnQ9InRleHQvaHRtbCIgY2hhcnNldD0iVVRGLTgiPgoJPG1ldGEgbmFtZT0idmlld3BvcnQiIGNvbnRlbnQ9IndpZHRoPWRldmljZS13aWR0aCwgaW5pdGlhbD0xIj4KCTxtZXRhIGh0dHAtZXF1aXY9IlgtVUEtQ29tcGF0aWJsZSIgY29udGVudD0iSUU9ZWRnZSI+Cgk8dGl0bGU+0J/RgNC+0LLQtdGA0LrQsCDRgdCy0Y/Qt9C4PC90aXRsZT4KPC9oZWFkPgo8Ym9keT4KCTxzcGFuPg=="},{"NodeType":1,"Pos":298,"Line":10,"Pipe":{"NodeType":14,"Pos":298,"Line":10,"IsAssign":false,"Decl":null,"Cmds":[{"NodeType":4,"Pos":298,"Args":[{"NodeType":8,"Pos":298,"Ident":["msg"]}]}]}},{"NodeType":0,"Pos":305,"Text":"PC9zcGFuPgo8L2JvZHk+CjwvaHRtbD4="}]}}},"text_tmpl":{"Tree":{"Name":"template.txt","ParseName":"template.txt","Root":{"NodeType":11,"Pos":0,"Nodes":[{"NodeType":1,"Pos":2,"Line":1,"Pipe":{"NodeType":14,"Pos":2,"Line":1,"IsAssign":false,"Decl":null,"Cmds":[{"NodeType":4,"Pos":2,"Args":[{"NodeType":8,"Pos":2,"Ident":["msg"]}]}]}}]}}},"context":{"msg":"Hi!"}}`
  err := json.Unmarshal([]byte(s), mail)

  fmt.Println(err)
  fmt.Println(mail)
}

Answer 1

template.Template不支持封送到JSON或从JSON封送。它是具有未导出字段的结构，并且未实现用于处理封送/拆送逻辑（例如template.Template）的接口。

您应该做的是在您的JSON和结构中包含源模板文本，然后解组源模板文本后，将其解析为后期处理步骤。如果要封送包含模板的结构，则它应仅包含源模板文本（json.Unmarshaler字段应标记为省略，如json.Unmarshaler）。