我正在尝试为汽车网站创建过滤器。我希望能够按外观颜色进行过滤。我使用外部表示数据库中的颜色。我的UL将数据库中的所有颜色都放入框中,并使每个颜色成为一个工业复选框。然后,我在页面上通过SELECT *语句列出所有汽车,然后通过包装和div的单个echo语句获取结果。我不想在此页面上的每辆汽车旁边显示我的外部颜色名称,因为我正在设计移动版本并试图保持其清洁。但是,我尝试将它们列为工业标签,但仍然发送到空白页。
<ul class="list-group">
<?php
$sql = "SELECT DISTINCT exterior FROM newcars ORDER BY exterior";
$result = $conn->query($sql);
while($row=$result->fetch_assoc()) {
?>
<li class="list-group-item">
<div class="form-check">
<label class="form-check-label">
<input type="checkbox" class="form-check-input product_check" name="" value="<?= $row['exterior']; ?>" id="exterior"><?= $row['exterior']; ?>
</label>
</div>
</li>
<?php
}
?>
</ul>
<div id="test">
<?php
$sql = "SELECT * FROM newcars";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_assoc($result)) {
echo ("<a href='newcarindex.php?id={$row['id']}'><div class='car'>");
echo '
<tr>
<td>
<img src="data:image\jpeg;base64,'.base64_encode($row['photo']).'"/>
</td>
</tr>
';
echo "<h2 class=car-name>";
echo $row['name'];
echo "</h2>";
echo "<span class=stock>STOCK#";
echo $row['stock'];
echo "</span>";
echo "<h3 class=car-msrp>";
echo $row['msrp'];
echo "</h3>";
echo "</div></a>";
}
} else {
echo "There are no matching results!";
}
?>
</div>
然后进入我的ajax脚本
<script type="text/javascript">
$(document).ready(function(){
$(".product_check").click(function(){
$("#loader").show();
var action = 'data';
var class = get_filter_text('class');
var body = get_filter_text('body');
var exterior = get_filter_text('exterior');
$.ajax({
url:'action.php',
method:'POST',
data:{action:action,class:class,body:body,exterior:exterior},
success:function(response){
$("#test").html(response);
$("loader").hide();
}
});
});
function get_filter_text(text_id){
var filterData = [];
$('#'+text_id+':checked').each(function(){
filterData.push($(this).val());
});
return filterData;
}
});
</script>
最后使用action.php页面连接到我的数据库并过滤结果
include 'dbh.php';
if(isset($_POST['action'])) {
$sql = "SELECT * FROM newcars WHERE class !=''";
if(isset($_POST['exterior'])) {
$exterior = implode("','", $_POST['exterior']);
$sql .="AND exterior IN('".$exterior."')";
}
$result = $conn->query($sql);
$output='';
if($result->num_rows>0){
while($row=$result->fetch_assoc()){
$photo = base64_encode($row['photo']);
$output .= "<a href='newcarindex.php?id={$row['id']}'>
<div class='car'>
<tr>
<td>
<img src='data:image\jpeg;base64,{$photo}'/>
</td>
</tr>
<h2 class='car-name'>{$row['name']}</h2>
<span class='stock'>STOCK#{$row['stock']}</span>
<h3 class='car-msrp'>{$row['msrp']}</h3>
</div></a>";
}
} else {
echo "There are no comments!";
}
}
?>
我遇到的问题是,每当我单击一种颜色以按页面进行过滤时,都会显示为空白,表示没有结果或错误。我在做什么错?
仅查看action.php,在成功查询后,我看不到$output
被回显。这是action.php
的完整代码吗?