NSString 中的子字符串[已关闭]

Question

我正在使用

NSString

，我想获取它的一个子字符串，其中包含字符串的前 20 个字符。我怎样才能做到这一点？

Answer 1

您可以使用

substringToIndex

。

NSString *mystring = @"This is a test message having more than 20 characters";
NSString *newString = [mystring substringToIndex:20];
NSLog(@"%@", newString);

Answer 2

NSString *str = @"123456789012345678901234";
NSString *subStr = [str substringWithRange:NSMakeRange(0, 20)];

Answer 3

NSString *string = @"I am having a simple question.I am having NSString and i want a substring of it that contains first 20 ";
NSString *first20CharString = [string substringToIndex:20];

Answer 4

试试这个：

NSString *string = @"This is for testing substring from string";
    NSInteger intIndex = 20;
    NSLog(@"%@", [string substringToIndex:intIndex]);

Answer 5

检查以下内容：

NSString *strTmp = @"This is test string to check substring.";
NSInteger intIdx = 20;
NSLog(@"%@", [strTmp substringToIndex:intIdx]);

这会对你有帮助。

干杯！