如果被字符包围,嵌入表达式不会被替换

问题描述 投票:0回答:1

在以下简化且非常基本的场景中,当附加、前置或被字符包围时,嵌入表达式不会被替换:

* def jobId = '0001'
* def out = 
        """
        {
            "jobId": "#(jobId)",
            "outputMetadata": {
                "fileName_OK": "#(jobId)",
                "fileName_Fail_1": "some_text_#(jobId)",
                "fileName_Fail_2": "#(jobId)-and-some-more-text",
                "fileName_Fail_3": "prepend #(jobId) and append"
            }
        }
        """
* print out

执行场景返回:

{
  "jobId": "0001",
  "outputMetadata": {
    "fileName_OK": "0001",
    "fileName_Fail_1": "some_text_#(jobId)",
    "fileName_Fail_2": "#(jobId)-and-some-more-text",
    "fileName_Fail_3": "prepend #(jobId) and append"
  }
}

这是一项功能、限制还是错误?或者,我错过了什么吗?

character karate
1个回答
1
投票

这是设计好的!你可以这样做:

"fileName_Fail_2": "#(jobId + '-and-some-more-text')"

任何有效的 JS 表达式都可以填充到嵌入表达式中,因此这不是限制。这只适用于 JSON 字符串值,或者当整个 RHS 是引号内的字符串并保持解析简单时。希望有帮助!

另请参阅:https://github.com/karatelabs/karate#rules-for-embedded-expressions

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