php准备好的语句返回空表

Question

我已经检查了连接及其工作。我也检查了数据库。有大约10条记录要显示。我使用了prepared语句，但是它返回一个空表。我一定在某个地方犯了错误，但找不到它。如果有人可以提供帮助，我将不胜感激。

<?php
            $stmt=$mysqli->prepare("SELECT id,carreg,make,model,price,enginesize,gearbox,fueltype,noofdoors,image1 FROM cars");
            $stmt->execute();
            $result = $stmt->get_result();
            while($row = $result->fetch_assoc())
            {
        ?>
            <tr>
                <td><img src="<?php echo $upload_dir_car.$row['image1'] ?>" height="110" width ="150" img-responsive></td>
                <td><?php echo $row['id'] ?></td>
                <td><?php echo $row['carreg'] ?></td>
                <td><?php echo $row['make'] ?></td>
                <td><?php echo $row['model'] ?></td>
                <td><?php echo $row['price'] ?></td>
                <td><?php echo $row['enginesize'] ?></td>
                <td><?php echo $row['gearbox'] ?></td>
                <td><?php echo $row['fueltype'] ?></td>
                <td><?php echo $row['noofdoors'] ?></td>
                <td>
                    <a class="btn btn-primary" href="car_edit.php?id=<?php echo $row['id'] ?>">
                        <i class="fas fa-edit fa-xs"></i>
                    </a>
                    <a class="btn btn-danger" href="car_manage.php?delete=<?php echo $row['id'] ?>" onclick="return confirm('Are you sure to delete this record?')">
                        <i class="fas fa-trash-alt fa-xs"></i>
                    </a>
                </td>
            </tr>
        <?php
            }
            $stmt->close();
        ?>

Answer 1

改正像这样的东西：

$sql = "SELECT id,carreg,make,model,price,enginesize,gearbox,fueltype,noofdoors,image1 FROM cars";
$result = $mysqli -> query($sql);

while($row = $result->fetch_assoc()){
   //your codes
}

您不需要prepare（）函数。