我有两张桌子:
TableA TableB
ID_A ID_B
P1 Text
P2
P3
P4
-
TableB
ID_B Text
1 A
2 B
3 C
4 D
5 E
6 F
7 G
-
TableA
ID_A P1 P2 P3 P4
1 7 5 6 6
感谢尼克帮助我USER Nick
SELECT a.*, b.*
FROM (SELECT ID_A, P1 AS P FROM TableA
UNION ALL
SELECT ID_A, P2 FROM TableA
UNION ALL
SELECT ID_A, P3 FROM TableA
UNION ALL
SELECT ID_A, P4 FROM TableA) p
JOIN TableA a ON a.ID_A = p.ID_A
JOIN TableB b ON b.ID_B = p.P
ORDER BY a.ID_A, b.ID_B
我明白了:
ID_A P1 P2 P3 P4 ID_B Text
1 7 5 6 6 5 E
1 7 5 6 6 6 F
1 7 5 6 6 6 F
1 7 5 6 6 7 G
我怎么能得到这个?
ID_A P1 P2 P3 P4 ID_B Text
1 7 5 6 6 7 G
1 7 5 6 6 5 E
1 7 5 6 6 6 F
1 7 5 6 6 6 F
1°行P1 = ID_B
2°行P2 = ID_B
3°行P3 = ID_B
4°行P4 = ID_B
发生这种情况是因为P
值的派生表中没有顺序。为了能够对此进行排序,我们可以添加另一个表示P
数字的字段(如P1
,P2
等)并按顺序排列而不是ID_B
:
SELECT a.*, b.*
FROM (SELECT 1 AS PNUM, ID_A, P1 AS P FROM TableA
UNION ALL
SELECT 2, ID_A, P2 FROM TableA
UNION ALL
SELECT 3, ID_A, P3 FROM TableA
UNION ALL
SELECT 4, ID_A, P4 FROM TableA) p
JOIN TableA a ON a.ID_A = p.ID_A
JOIN TableB b ON b.ID_B = p.P
ORDER BY a.ID_A, p.PNUM
输出:
ID_A P1 P2 P3 P4 ID_B Text
1 7 5 6 6 7 G
1 7 5 6 6 5 E
1 7 5 6 6 6 F
1 7 5 6 6 6 F
您可以使用CASE
,WHEN
作为自定义排序顺序。这将在期望的排序中显示结果
SELECT a.*, b.*
FROM (SELECT ID_A, P1 AS P FROM TableA
UNION ALL
SELECT ID_A, P2 FROM TableA
UNION ALL
SELECT ID_A, P3 FROM TableA
UNION ALL
SELECT ID_A, P4 FROM TableA) p
JOIN TableA a ON a.ID_A = p.ID_A
JOIN TableB b ON b.ID_B = p.P
ORDER BY CASE b.ID_B
WHEN 7 THEN 4
WHEN 5 THEN 3
ELSE 2
END DESC
SELECT * FROM TableA as a1
left join TableB as b1 on ID_B = p1
union ALL
SELECT * FROM TableA
left join TableB on ID_B = p2
union ALL
SELECT * FROM TableA
left join TableB on ID_B = P3
union ALL
SELECT * FROM TableA
left join TableB on ID_B = p4