如何导入使用当前文件中定义的变量的函数?
卖弄.朋友
from functions import a
x = 1
print(a())
functions.朋友
def a():
return x
错误信息
Traceback (most recent call last):
File "c:\Users\Test\.vscode\extensions\ms-python.python-2019.4.11987\pythonFiles\ptvsd_launcher.py", line 43, in <module>
main(ptvsdArgs)
File "c:\Users\Test\.vscode\extensions\ms-python.python-2019.4.11987\pythonFiles\lib\python\ptvsd\__main__.py", line 410, in main
run()
File "c:\Users\Test\.vscode\extensions\ms-python.python-2019.4.11987\pythonFiles\lib\python\ptvsd\__main__.py", line 291, in run_file
runpy.run_path(target, run_name='__main__')
File "C:\Users\Test\AppData\Local\Programs\Python\Python37\lib\runpy.py", line 263, in run_path
pkg_name=pkg_name, script_name=fname)
File "C:\Users\Test\AppData\Local\Programs\Python\Python37\lib\runpy.py", line 96, in _run_module_code
mod_name, mod_spec, pkg_name, script_name)
File "C:\Users\Test\AppData\Local\Programs\Python\Python37\lib\runpy.py", line 85, in _run_code
exec(code, run_globals)
File "c:\Users\Test\Google Drive\Dev\Test\main.py", line 5, in <module>
print(a())
File "c:\Users\Test\Google Drive\Dev\Test\functions.py", line 2, in a
return x
NameError: name 'x' is not defined
正如另一个答案所指出的那样,由于Python范围变量的原因,这将不起作用。
因此,我建议您将所有这些变量移动到单独的文件中,例如, constants.py
:
main.py
from functions import a
print(a())
constants.py
X = 1
functions.py
from constants import X
def a():
return X
然后,运行import main
打印1
。
没有进程范围的全局变量,只有模块级全局变量。 a
使用functions.x
,而不是x
在任何全球范围内调用它。
import functions
from functions import a, b, c
functions.x = 1
functions.y = 2
functions.z = 3
print(a())
print(b())
print(c())
因为Python是词法范围的,所以每个函数都会引用它所定义的全局范围。名称查找使用该范围来解析自由变量。