class Twitter {
static connect() async {
final String textToTweet =
'Hello, Twitter! This is a tweet from my Flutter app!';
final Uri twitterUrl =
Uri.parse('https://twitter.com/intent/tweet?text=$textToTweet');
if (await canLaunchUrl(twitterUrl)) {
await launchUrl(twitterUrl);
} else {
throw 'Could not launch $twitterUrl';
}
}
}
这个函数不会在 flutter 中打开推特,请在我调用这个函数时帮助打开推特
网址启动器问题可能