如何列出那些ID在where子句中没有的内容？

Question

我有2张桌子书和副本。我计算了那些副本的2个日期之间的时间，并按bookID分组，两个日期之间有什么，我得到以下结果：

• BookID复制数量
• 111111 1
• 222222 888
• 333333 666

  SELECT BookID, Count(CopyID)
   from Copy 
   INNER join Book on Book.BookID = Copy.BookdID
   where Copy.Time BETWEEN '2017.12.11' AND '2017.12.15'
  GROUP BY BOOKID

这是我的问题：我想计算所有副本在我的查询中有相同的BookID。例如：我有BookID 111111的1个结果，但是如果有8个副本我想以某种方式包括我的结果。

Answer 1

Ben，以下查询显示书籍的所有副本的计数，其中给定的两个日期之间至少有一个副本

请检查它是否输出所需的内容

select
    b.BookID, Count(c.CopyID)
from Book as b
left outer join Copy as c
    on b.BookID = c.BookID
where b.BookID in (
    select
        distinct c.BookID
    from Copy as c
    where c.Time BETWEEN '2017.12.11' AND '2017.12.15'
)
group by
    b.BookID

Answer 2

我认为你甚至不需要预订餐桌

select c.ID, count(*)
from copy c 
where exists ( select 1 
                 from copy 
                where copy.ID = c.ID 
                  and copy.Time BETWEEN '2017.12.11' AND '2017.12.15' 
             )
group by c.ID