将响应插入空列表

Question

我是 python 新手，我正在编写一段代码，通过从项目中列出它们来连接到 gke 集群。但是，当我尝试将 gke 集群存储到列表中时，我收到错误 NameError: name 'name' is not Define 。但是当我检查 cluster[name] 的类型时，它给了我 string 。有人可以帮我解决这个问题吗？下面是代码片段

  with open("abc.txt", "r") as f:
   for x in f:
    subprocess.run(["gcloud", "config" ,"set" ,"project",x ])
    request = service.projects().zones().clusters().list(projectId=x, zone='-')
    response = request.execute()
    if 'clusters' in response:
        for cluster in response['clusters']:
            li = []
            li.append(cluster[name])
            print(li)

打印集群给了我这样的结果

{'name': 'gke-name', 'nodeConfig': {'machineType': 'machine-type', 'diskSizeGb': 100, 'oauthScopes': ['https://www.googleapis.com/auth/cloud-platform'], 'metadata': {'VmDnsSetting': 'ZonalPreferred', 'serial-port-logging-enable': 'false'} }

Answer 1

集群的响应是一个字典，它的键是一个字符串，所以

name

中的

cluster[name]

应该用双引号

""

或单引号

''

。或者您可以将其定义为变量。

with open("abc.txt", "r") as f:
    for x in f:
        subprocess.run(["gcloud", "config", "set", "project", x])
        request = service.projects().zones().clusters().list(projectId=x, zone='-')
        response = request.execute()
        if 'clusters' in response:
            for cluster in response['clusters']:
                li = []
                li.append(cluster['name'])  # Accessing 'name' key correctly
                print(li)