Spring Security 5 与 oauth2 导致“principalName 不能为空”错误

问题描述 投票：0回答：3

我正在尝试使用 Spring Security 5 实现一个受 oauth2 保护的 Spring Boot API。我希望该 API 成为一个 oauth2 资源服务器，并且能够使用 WebClient 访问外部 oauth2 资源服务器，并授予客户端凭据。

我可以将 API 配置为 oauth2 资源服务器或 oauth2 客户端，但不能同时配置两者。

下面是将 API 配置为具有 Spring security 5 的资源服务器的最小设置。我使用的是不透明令牌，因此服务器已为此配置。

应用程序.属性

spring.security.oauth2.resourceserver.opaquetoken.introspection-uri=http://localhost:8086/auth/oauth/check_token
spring.security.oauth2.resourceserver.opaquetoken.client-id=test-api
spring.security.oauth2.resourceserver.opaquetoken.client-secret=e61aa5d6-074d-4216-b15f-1bf3fc71b833

WebSecurity配置类

@EnableWebSecurity
public class WebSecurity extends WebSecurityConfigurerAdapter {
    
    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
            .authorizeRequests(authorizeRequests ->
                    authorizeRequests
                        .anyRequest().authenticated()
            )
            .oauth2ResourceServer(OAuth2ResourceServerConfigurer::opaqueToken);

    }
}

通过此设置，我可以使用有效令牌访问此 api 端点以访问其受保护的资源。因此资源服务器配置本身就可以正常工作。

下面是配置为使用 WebClient 的最小 Spring security 5 设置，通过客户端凭据授予来访问外部受保护资源。

应用程序.属性

spring.security.oauth2.client.provider.my-oauth-provider.token-uri=http://127.0.0.1:8086/auth/oauth/token
spring.security.oauth2.client.registration.test-api.client-id=test-store
spring.security.oauth2.client.registration.test-api.client-secret=password
spring.security.oauth2.client.registration.test-api.provider=my-oauth-provider
spring.security.oauth2.client.registration.test-api.scope=read,write
spring.security.oauth2.client.registration.test-api.authorization-grant-type=client_credentials

WebSecurity配置类

@EnableWebSecurity
public class WebSecurity extends WebSecurityConfigurerAdapter {
    
    @Autowired
    ClientRegistrationRepository clientRegistrationRepository;
    
    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
            .oauth2Client(oauth2 -> oauth2
                .clientRegistrationRepository(clientRegistrationRepository)
            );
    }
}

Oauth2Client配置类

@Configuration
public class Oauth2ClientConfig {
    
    @Bean
    public OAuth2AuthorizedClientManager authorizedClientManager(
            ClientRegistrationRepository clientRegistrationRepository,
            OAuth2AuthorizedClientRepository authorizedClientRepository) {

        OAuth2AuthorizedClientProvider authorizedClientProvider =
                OAuth2AuthorizedClientProviderBuilder.builder()
                        .clientCredentials()
                        .build();

        DefaultOAuth2AuthorizedClientManager authorizedClientManager =
                new DefaultOAuth2AuthorizedClientManager(
                        clientRegistrationRepository, authorizedClientRepository);
        authorizedClientManager.setAuthorizedClientProvider(authorizedClientProvider);

        return authorizedClientManager;
    }

    
    @Bean
    WebClient webClient(OAuth2AuthorizedClientManager oAuth2AuthorizedClientManager) {
        ServletOAuth2AuthorizedClientExchangeFilterFunction oauth2Client =
                new ServletOAuth2AuthorizedClientExchangeFilterFunction(
                        oAuth2AuthorizedClientManager);
        
        // default registrationId
       oauth2Client.setDefaultClientRegistrationId("test-api");
        
        // set client to use oauth2 by default globally
       oauth2Client.setDefaultOAuth2AuthorizedClient(true);
        
        return WebClient.builder()
          .apply(oauth2Client.oauth2Configuration())
          .build();
    }
}

通过此设置，我可以使用客户端凭据授予访问外部受保护端点以访问受保护资源。

但是，当我将这两个配置放在一起时，当我尝试访问我的 api 端点（该端点又尝试使用 WebClient 访问外部资源）时，它不起作用。

    @Autowired
    WebClient webClient;

    @GetMapping("test")
    public String test() {
        String message = webClient
                .get()
                .uri("http://localhost:8084/external/api/endpoint")
                .retrieve()
                .bodyToMono(String.class)
                .block();
        return message;
    }

Spring 安全性抛出 principalName 不能为空 错误。


java.lang.IllegalArgumentException: principalName cannot be empty
    at org.springframework.util.Assert.hasText(Assert.java:287) ~[spring-core-5.2.8.RELEASE.jar:5.2.8.RELEASE]
    Suppressed: reactor.core.publisher.FluxOnAssembly$OnAssemblyException: 
Error has been observed at the following site(s):
    |_ checkpoint ⇢ Request to GET http://localhost:8084/ocr/document/test [DefaultWebClient]
Stack trace:
        at org.springframework.util.Assert.hasText(Assert.java:287) ~[spring-core-5.2.8.RELEASE.jar:5.2.8.RELEASE]
        at org.springframework.security.oauth2.client.InMemoryOAuth2AuthorizedClientService.loadAuthorizedClient(InMemoryOAuth2AuthorizedClientService.java:73) ~[spring-security-oauth2-client-5.3.3.RELEASE.jar:5.3.3.RELEASE]
        at org.springframework.security.oauth2.client.web.AuthenticatedPrincipalOAuth2AuthorizedClientRepository.loadAuthorizedClient(AuthenticatedPrincipalOAuth2AuthorizedClientRepository.java:73) ~[spring-security-oauth2-client-5.3.3.RELEASE.jar:5.3.3.RELEASE]
        at org.springframework.security.oauth2.client.web.DefaultOAuth2AuthorizedClientManager.authorize(DefaultOAuth2AuthorizedClientManager.java:144) ~[spring-security-oauth2-client-5.3.3.RELEASE.jar:5.3.3.RELEASE]
        at org.springframework.security.oauth2.client.web.reactive.function.client.ServletOAuth2AuthorizedClientExchangeFilterFunction.lambda$authorizeClient$24(ServletOAuth2AuthorizedClientExchangeFilterFunction.java:534) ~[spring-security-oauth2-client-5.3.3.RELEASE.jar:5.3.3.RELEASE]
...

非常感谢任何有关解决此问题的指示。当 API 也是资源服务器时，我应该使用不同的方式配置 WebClient 来工作吗？

我的 Maven 项目中有这些依赖项。 Spring安全版本是5.3.3.RELEASE pom.xml

    <parent>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-parent</artifactId>
        <version>2.3.2.RELEASE</version>
        <relativePath/> <!-- lookup parent from repository -->
    </parent>

    ...

        <!-- Spring Boot Web starter -->
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-web</artifactId>
        </dependency>
        <!-- Security Starter -->
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-security</artifactId>
        </dependency>
        <!-- Oauth2 resource server -->
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-oauth2-resource-server</artifactId>
        </dependency>
        <dependency>
            <groupId>com.nimbusds</groupId>
            <artifactId>oauth2-oidc-sdk</artifactId>
        </dependency>
        <!-- Oauth2 client -->
        <dependency>
            <groupId>org.springframework.security</groupId>
            <artifactId>spring-security-oauth2-client</artifactId>
        </dependency>
        <!-- WebClient -->
        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-webflux</artifactId>
        </dependency>
spring-boot spring-security oauth-2.0 spring-security-oauth2 spring-webclient
3个回答
2
投票

从这里： https://www.gitmemory.com/issue/spring-projects/spring-security/8398/614615036

这是预期行为 ->“principalName 不能为空”。

OAuth2AuthorizedClient 需要principalName，因为访问 令牌始终与主体相关联。这 ReactiveOAuth2AuthorizedClientService 验证principalName 和 如果principalName不可用，预计会失败。

principalName 不可用的原因是 JwtAuthenticationToken.getName() 将默认为 sub 声明，其中 根据您的令牌，在 Jwt 的声明集中不可用 上面的例子。您需要做的是指定 user_name 声明 用作principalName。

看看这个 样品 这向您展示了如何将 JwtDecoder 配置为默认值 JwtAuthenticationToken.getName() 的 user_name。

链接的示例无法按原样工作，因为 conversionClaims 中没有“user_name”值，所以我只是编写了自己的用户名。 这是我添加到配置中的内容：

http.authorizeExchange(exchangeSpec -> exchangeSpec.anyExchange().authenticated())
                .oauth2ResourceServer(oAuth2 -> oAuth2.jwt(jwt -> jwt.jwtDecoder(jwtDecoder())));
http.oauth2Login();

和

public class UsernameSubClaimAdapter implements Converter<Map<String, Object>, Map<String, Object>> {
    private final MappedJwtClaimSetConverter delegate =
            MappedJwtClaimSetConverter.withDefaults(Collections.emptyMap());

    public Map<String, Object> convert(Map<String, Object> claims) {
        Map<String, Object> convertedClaims = this.delegate.convert(claims);

        String username = "anonymous_user";
        convertedClaims.put("sub", username);

        return convertedClaims;
    }
}

@Bean
public NimbusReactiveJwtDecoder jwtDecoder() {
    NimbusReactiveJwtDecoder jwtDecoder = new NimbusReactiveJwtDecoder(processor());
    jwtDecoder.setJwtValidator(JwtValidators.createDefaultWithIssuer(_jwtIssuerUrl));
    jwtDecoder.setClaimSetConverter(new UsernameSubClaimAdapter());
    return jwtDecoder;
}
0
投票

问题是您的应用程序同时是 

resourceServer
和 
oauth2Client
，这听起来很奇怪。 将 
.oauth2ResourceServer(OAuth2ResourceServerConfigurer::opaqueToken)
配置包含到 
httpSecurity
中后，所有身份验证现在都将是 
BearerTokenAuthentication
的实例。这些不会有与之关联的名称，因为您的不透明令牌没有 
name
字段。如果您排除 
.oauth2ResourceServer(OAuth2ResourceServerConfigurer::opaqueToken)
，则所有身份验证都将是 
AnonymousAuthenticationToken
的实例，并具有默认主体 
anonymousUser
。

此问题的解决方案是实现您自己的不透明令牌内省器，它将为身份验证设置主体名称。我通过扩展 

NimbusReactiveOpaqueTokenIntrospector
并使用默认主体名称复制 Oauth2Authentication 来快速而肮脏地完成此操作。

内省者：

class ExtendedNimbusReactiveOpaqueTokenIntrospector(introspectionUri: String, clientId: String, clientSecret: String) : NimbusReactiveOpaqueTokenIntrospector(introspectionUri, clientId, clientSecret) {
    override fun introspect(token: String?): Mono<OAuth2AuthenticatedPrincipal> {
        return super.introspect(token).map { auth ->
            val name = SecurityContextHolder.getContext().authentication?.name ?: "defaultPrincipal"
            DefaultOAuth2AuthenticatedPrincipal(name, auth.attributes, auth.authorities)
    }
}

}

网络安全配置：

@Configuration
@EnableWebFluxSecurity
class OAuthConfig
@Autowired constructor(@Value("\${spring.security.oauth2.resourceserver.opaquetoken.introspection-uri}") private val introspectionUri: String,
                   @Value("\${spring.security.oauth2.resourceserver.opaquetoken.client-id}") private val clientId: String,
                   @Value("\${spring.security.oauth2.resourceserver.opaquetoken.client-secret}") private val clientSecret: String){

    @Bean
    fun securityWebFilterChain(http: ServerHttpSecurity): SecurityWebFilterChain {
        return http
            .oauth2Client {

            }
            .authorizeExchange { authExchange ->
                authExchange.pathMatchers(
                        "/apidoc",
                        "/swagger-ui.html",
                        "/webjars/**",
                        "/swagger-resources/**",
                        "/v2/api-docs")
                        .permitAll()
                        .anyExchange()
                        .permitAll()
            }
            .oauth2Client {}
            .oauth2ResourceServer {
                it.opaqueToken {opaqueTokenSpec ->
                    opaqueTokenSpec.introspector(ReweNimbusReactiveOpaqueTokenIntrospector(introspectionUri, clientId, clientSecret))
                }
            }
            .build()
    }

}

Web客户端配置：

@Configuration
class WebClientConfig @Autowired constructor() {

    @Bean
    fun authorizedClientManager(
            clientRegistrationRepository: ReactiveClientRegistrationRepository?,
            authorizedClientService: ReactiveOAuth2AuthorizedClientService?
    ): ReactiveOAuth2AuthorizedClientManager? {
        val authorizedClientProvider = ReactiveOAuth2AuthorizedClientProviderBuilder.builder()
            .clientCredentials()
            .build()
        val authorizedClientManager = AuthorizedClientServiceReactiveOAuth2AuthorizedClientManager(clientRegistrationRepository, authorizedClientService)
        authorizedClientManager.setAuthorizedClientProvider(authorizedClientProvider)
        return authorizedClientManager
    }

    @Bean
    fun webClientBuilder(authorizedClientManager: ReactiveOAuth2AuthorizedClientManager?): WebClient.Builder? {
        val oauth = ServerOAuth2AuthorizedClientExchangeFilterFunction(authorizedClientManager)
    oauth.setDefaultClientRegistrationId("rewe")
        return WebClient.builder()
            .filter(oauth)
    }

    @Bean
    fun authorizedWebClient(webClientBuilder: WebClient.Builder, @Value("\${host}") host: String): WebClient {
        return webClientBuilder.baseUrl(host).build()
    }
}
0
投票

我不知道这是否适用于您的情况，但我遇到了同样的问题，我通过将 @Async 放在负责使用 WebClient 执行请求的服务上来修复它。 IE。如果您传递到另一个线程，则身份验证上下文将被清除，您将不再尝试将其作为下游授权的上下文传递。

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