Ruby搜索http get请求响应体

问题描述 投票:1回答:2

我正在红宝石中提出请求;

    require 'net/http'
    require 'uri'

    uri = URI.parse("https://www.test.com")
    request = Net::HTTP::Get.new(uri)
    request.content_type = "application/json"
    request["Accept"] = "application/json"

    req_options = {
      use_ssl: uri.scheme == "https",
    }

    response = Net::HTTP.start(uri.hostname, uri.port, req_options) do |http|
      http.request(request)
    end

    # response.code
    response.body

这是一个html源返回纯文本。我想在这个返回上搜索一些id元素并获得它的值。它似乎是一个爬虫。但我从未写过一篇。

例如,有一个像;

<div id='price'>1000€</div>

我想搜索<div id='price'>并获得1000欧元。

我只能得到它的索引。但后来不知道该怎么办。

可能吗 ?或者还有其他方法吗?

谢谢

ruby https xmlhttprequest web-crawler
2个回答
0
投票

在Ruby中我们有Nokogiri,它允许您通过XPath或CSS3选择器搜索文档:

doc = Nokogiri::HTML(open("https://www.test.com"))
doc.at_css('div#price').text

要么:

doc = Nokogiri::HTML response.body
doc.at_css('div#price').text

https://github.com/sparklemotion/nokogiri


0
投票

你可能想用https://github.com/sparklemotion/nokogiri gem。

Nokogiri(锯)是一个Rubygem,提供支持XPath和CSS选择器的HTML,XML,SAX和Reader解析器。

require 'nokogiri'

html = <<HTML
<div id="block1">
    <a href="http://google.com">link1</a>
</div>
<div id="block2">
    <a href="http://stackoverflow.com">link2</a>
    <a id="tips">just a bookmark</a>
</div>
HTML

doc = Nokogiri::HTML(html)
doc.css('#block1 a[href]').text
#=>link1

要修改您的示例:

require 'net/http'
require 'uri'
require 'nokogiri'
uri = URI.parse("https://www.example.com")
request = Net::HTTP::Get.new(uri)
request.content_type = "application/json"
request["Accept"] = "application/json"

req_options = {
  use_ssl: uri.scheme == "https",
}

response = Net::HTTP.start(uri.hostname, uri.port, req_options) do |http|
  http.request(request)
end

response.body

doc = Nokogiri::HTML.parse(response.body)

doc.css('p').text;
#=> "This domain is established to be used for illustrative examples in documents. You may use this\n    domain in examples without prior coordination or asking for permission.More information..."
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