要识别的SQL

Question

这是我正在使用的桌子：

customer_id  order_id    order_date
101              1       2016-12-11
102              2       2016-12-13
101              3       2017-12-14
103              4       2017-12-15
...             ...           ...

我需要一个SQL来找出在2016年和2017年有多少客户购买了X次以上的商品。

我已经得到了正确的答案，它是客户101，使用以下代码：

select
    customer_id
from 
(
    select  
        year(order_date) as order_date_year,
        customer_id,
        count(*) as number_of_orders
    from
        cust_orders
    group by
        year(order_date),
        customer_id
    having
        count(*) >= 3
) as t
group by
    order_date_year,
    customer_id

但是这并不能解决特定年份超过X的问题。

感谢您的任何帮助，谢谢！

Answer 1

您需要2级汇总：

select c.customer_id
from (
  select customer_id
  from cust_orders 
  where year(order_date) in (2016, 2017)
  group by customer_id, year(order_date)
  having count(*) >= 10
) c
group by c.customer_id
having count(*) = 2;

用购买数量代替10。将2更改为要搜索的年数。参见demo。

Answer 2

您可以将聚合与having子句一起使用，以按年份和客户获取计数。然后再次汇总并计算年份：

select customer_id
from (select customer_id, year(order_date) as year
      from cust_orders co
      group by customer_id, year(order_date)
      having count(*) >= X
     ) x
where year in (2016, 2017)
group by customer_id
having count(*) = 1;