在Powershell AD脚本中切换姓氏，名字

Question

我尝试通过Firstname，Lastname从OU导出AD组和用户，但我只能使用Lastname，Firstname。

我尝试的其他所有内容都为我提供了一个空字符串。我尝试将Select-Object下的行更改为：

@{Name='Member';Expression={$_.FirstName = GetFirstName $_.Name $_.LastName = GetLastName $_.Name}},

$firt = $_.firstname
$last = $_.lastname
@{Name='Member';Expression={$_.name = "$first,$last"}}, 

这是工作代码，但应切换名称。

$OU = 'OU=Groups,OU=City,OU=Continent,DC=DomainControler, DC=Domain, DC=net' #Change this to get different groups
$DateTime = Get-Date -f "dd-MM-yyyy" 

$MyFileName = "CompanyName-Groups_"+$DateTime+".csv"
$Path = Join-Path $PSScriptRoot $MyFileName

$Groups =  get-adobject -Filter 'ObjectClass -eq "group"' -SearchBase $OU
$i=0
$tot = $Groups.count
$Data = foreach ($Group in $Groups) {
    $i++ 
    $status = "{0:N0}" -f ($i / $tot * 100) 
    Write-Progress -Activity "Exporting AD Groups" -status "Processing Group $i of $tot : $status% Completed" -PercentComplete ($i / $tot * 100) 
    Get-ADGroupMember -Identity $Group | 
    Select-Object @{Name='Group';Expression={$Group.Name}}, 
                  @{Name='Member';Expression={$_.Name}}, 
                  @{Name='Enabled';Expression={if ($_.ObjectClass -eq 'user') {Get-ADUser $_ | Select-Object -Expand Enabled} else {'NA/Group'}}}
    }
$Data | Export-Csv -Path $Path -NoTypeInformation

这是一个示例输出：

Group, "member", enabled
Admin, "Mario, Speedwagon", True
Admin, "Petey, Cruiser", True
Admin, "Anna, Sthesia", False
HR, "Paul, Molive", True
HR, "Phaedra, Lugt", True
IT, "Paul, Molive", False
IT, "Cliff, Hanger", True

它应该成为：

Group, "member", enabled
Admin, "Speedwagon, Mario", True
Admin, "Cruiser, Petey", True
Admin, "Sthesia, Anna", False
HR, "Molive, Paul", True
HR, "Lugt, Phaedra", True
IT, "Molive, Paul", False
IT, "Hanger, Cliff", True

Answer 1

我想这可能会让你感到清楚：

$OU = 'OU=Groups,OU=City,OU=Continent,DC=DomainControler, DC=Domain, DC=net'

$PathParams = @{
    Path      = $PSScriptRoot
    ChildPath = "PA-AD-Groups_{0}.csv" -f (Get-Date -f "dd-MM-yyyy")
}
$FilePath = Join-Path @PathParams

$Groups = Get-ADObject -Filter 'ObjectClass -eq "group"' -SearchBase $OU
$i = 0
$tot = $Groups.count

$Data = foreach ($Group in $Groups) {
    $i++
    $ProgressParams = @{
        Activity        = 'Exporting AD Groups'
        PercentComplete = ($i / $tot * 100)
        status          = "Processing Group $i of $tot : {0:N0} Completed" -f
        ($i / $tot * 100)
    }
    Write-Progress @ProgressParams

    Get-ADGroupMember -Identity $Group |
        Select-Object @{Name = 'Group'; Expression = {$Group.Name}},
    @{Name = 'Member'; Expression = {$_.Name}},
    @{Name = 'Enabled'; Expression = {
            $Script:User = $false
            if ($_.ObjectClass -eq 'user') {
                $Script:User = Get-ADUser $_
                if ($User.Enabled) {$true} else {$false}
            }
            else {
                'NA/Group'
            }
        }
    },
    @{Name = 'FirstName'; Expression = {
            if ($User) {
                $User.GivenName
            }
        }
    },
    @{Name = 'LastName'; Expression = {
            if ($User) {
                $User.Surname
            }
        }
    },
    @{Name = 'CombinedName'; Expression = {
            if ($User) {
               "{0}, {1}" -f $User.GivenName, $User.Surname
            }
        }
    }
}

$Data | Export-Csv -Path $FilePath -NoTypeInformation

你遇到的问题是你不能在$User中使用Expression之外的Select-Object属性。这可以通过创建一个在整个脚本中可用的变量来修复，因此称为Script scope，用作$Script:User。

更多信息可以在Get-Help about_Scopes或here找到。

在旁注中我会建议你使用适当的缩进，它使事情更具可读性。 splatted参数hashtable也在这方面有所帮助。作为最后一个提示：如果您只使用一次，请不要创建变量。否则它只会让你后悔。