替代路线到禁止的防护路线?

问题描述 投票:0回答:1

对于下面的路由器,当/禁止访问路由AdalGuard或其子路由之一时,是否可以设置替代路由(例如,例如/int

我知道我可以在保护类内部执行此操作,方法是在保护类内部调用.navigateByUrl()或返回UrlTree。但是在这种情况下,AdalGuard来自程序包“ adal-angular4”,所以我不能这样做。

是否有指向其他路由的类似“ Else”或“ Catch”的指针,可以放入受保护路由的定义之内?

非常感谢。

app-routing.module.ts

import { NgModule } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';
import { ExtMainComponent } from './ext/ext-main/ext-main.component';
import { IntMainComponent } from './int/int-main/int-main.component';
import { EmailSenderComponent } from './int/email-sender/email-sender.component';
import { AdalGuard } from 'adal-angular4';

const routes: Routes = [
    {path: 'ext', component: ExtMainComponent},
    {
        path: 'int', component: IntMainComponent, canActivate: [AdalGuard], children: [
            {path: 'email', component: EmailSenderComponent}
        ]
    },
    {path: '**', redirectTo: '/'}
];

@NgModule({
    imports: [RouterModule.forRoot(routes)],
    exports: [RouterModule]
})
export class AppRoutingModule {
}

angular angular-router angular9
1个回答
0
投票

AdalGuard本身很简单,如果您查看source code

您可以将其分叉或扩展。我会分叉它,以便您可以完全控制该功能。

import { Injectable } from '@angular/core';
import { Router, UrlTree, ActivatedRouteSnapshot, CanActivate, CanActivateChild, RouterStateSnapshot } from '@angular/router';
import { Observable } from 'rxjs';
import { AdalService } from './adal.service';

@Injectable()
export class MyAdalGuard implements CanActivate, CanActivateChild {

  constructor(private adalService: AdalService,
    private router: Router
  ) { }

  canActivate(
    route: ActivatedRouteSnapshot,
    state: RouterStateSnapshot
  ): boolean | UrlTree {
    if (this.adalService.userInfo.authenticated) {
      return true;
    }

    return this.router.parseUrl('/some-url');
  }

  public canActivateChild(
    childRoute: ActivatedRouteSnapshot,
    state: RouterStateSnapshot
  ): boolean | UrlTree {
    return this.canActivate(childRoute, state);
  }
}
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