PHP验证检查

Question

我试图为我正在工作的网站创建一个验证表单，并且如果帖子请求在没有验证的情况下工作，那么只要我开始引入一个简单的计数来阻止查询被发送，它就会停止工作

<?php
$ErrorCount = 0;
$StudentNO = $_POST['updateid'];
$editfirst = $_POST['updatefirst'];
$editSurname = $_POST['updatesurn'];


$editfirst = test_input($editfirst);
$editSurname = test_input($editSurname);
$StudentNO = test_input2($StudentNO);

function test_input($data) {
    $data = trim($data);
    $data = stripslashes($data);
    $data = htmlspecialchars($data);
    $data = preg_replace("/[^a-zA-Z]/", "", $data);
    if(preg_match('/drop table/i', $data)) {
        $data == null;
    }
    if($data == null) {
        $ErrorCount++;
    }
}

function test_input2($data) {
    $data = trim($data);
    $data = stripslashes($data);
    $data = htmlspecialchars($data);
    $data = preg_replace("/[^a-zA-Z]/", "", $data);
    if(preg_match('/drop table/i', $data)) {
        $data == null;
    }
    if(strlen($StudentNO) != 6) {
        $ErrorCount++;
    }
    if($data == null) {
        $ErrorCount++;
    }
}


if($ErrorCount == 0) {
    $server = 'sql.rde.hull.ac.uk';
    $connectionInfo = array("Database"=>"rde_556278");
    $conn = sqlsrv_connect($server, $connectionInfo);

    $updateQuery = "UPDATE Users SET Firstname = '$editfirst', Surname = '$editSurname' WHERE StudentID = '$StudentNO';";
    $result = sqlsrv_query($conn, $updateQuery);

    sqlsrv_free_stmt( $updateQuery);
    sqlsrv_close($conn);
}
?>

问题是错误计数没有被增加或传递给任何东西，任何帮助，因为我无法看到我的错误。我是非常新的PHP

<?php
updateQuery = "INSERT INTO Locations (StudentID, ,[Location], [DateTime]) VALUES (?, ?, GETDATE());";
$params = array($UpdateStudent, $UpdateLocation);
$result = sqlsrv_query($conn, $updateQuery, $params);
?>    

Answer 1

您是否尝试将功能定义更改为：

function test_input($data,$ErrorCount) { /*code....*/ }

function test_input2($data,$ErrorCount) { /*code....*/ }