将参数发送到BroadcastReceiver并在onReceive方法中检查它

Question

我正在尝试在循环中发送大量sms消息，并且对于每个消息，我需要注册braodcaseReceiver，以检测已发送或已接收状态。

我需要将消息id的值发送到broadcastReceiver，以便能够将该消息标记为已发送。

如何将“id”的值传递给BroadcastReceiver？

代码如下：

...
// message id will be different for each time a message is sent
String id = "101"; 

String SENT = "SMS_SENT";
String DELIVERED = "SMS_DELIVERED";

Intent sentIntent = new Intent(SENT);
Intent deliveredIntent = new Intent(DELIVERED);

PendingIntent sentPI = PendingIntent.getBroadcast(mContext, 0, sentIntent, 0);
PendingIntent deliveredPI = PendingIntent.getBroadcast(mContext, 0, deliveredIntent, 0);

mContext.registerReceiver(
    new BroadcastReceiver()
    {
        @Override public void onReceive(Context arg0, Intent intent)
        {
            //I need to check the id of the message here 
            switch(getResultCode())
            {
                case Activity.RESULT_OK:
                    //updateSmsSentStatus(id);
                    break;
                ...
             }
             unregisterReceiver(this);
         }
    }, new IntentFilter(SENT));

SmsManager smsManager = SmsManager.getDefault();
smsManager.sendTextMessage(destinationAddress, scAddress, smsMessage, sentPI, deliveredPI);

注意：

要为问题添加更多上下文：

• 上面的代码在AsyncTask类中。该任务被多次调用以异步发送多个消息。
• 我尝试将消息id作为额外发送到sentIntent并在onReceive中接收它（类似于Girish的答案），但我实际上只重复接收了一个值。

Answer 1

在创建Intent对象时，您可以将Id存储在Intent中，如下所示，

Intent sentIntent = new Intent(SENT);
// assuming id is of type int
intent.putExtra("Id", id);

然后在onReceive方法，

public void onReceive(Context arg0, Intent intent)
{
  int id = intent.getIntExtra("Id", -1); 
  // above -1 default value is returned if "Id" doesn't exist.

  //I need to check the id of the message here 
  switch(getResultCode())
    {
      case Activity.RESULT_OK:
        //updateSmsSentStatus(id);
        break;
        ...
     }
     unregisterReceiver(this);
}