MySQLi / PHP 表过滤结果查询

Question

我希望在输入要搜索的值后过滤结果，以便表标题链接仅返回搜索结果。目前它返回整个表。 我该怎么做？通过将表单从 post 更改为 get？有什么想法吗？

编辑**** 我没有很好地解释自己。 通常该表会显示 20 多条记录，可以通过单击表头对这些记录进行排序。搜索完成后，我希望表头仅对搜索结果进行排序。 IE。如果我搜索“汤姆”，它返回了 3 个结果，我希望标题中的链接只对这 3 个返回的结果进行排序 ****

谢谢。

<?php


include 'dbconnect.php';

if(isset($_POST['search'])) {

$valueToSearch = mysqli_real_escape_string($db, $_POST['valueToSearch']);
// search in all table columns
// using concat mysql function
$sql = "SELECT * FROM contacts 
        WHERE CONCAT(FirstName, Surname, Email, HomePhone, MobPhone) 
        LIKE '%".$valueToSearch."%'";

$query = mysqli_query($db,$sql);

} else {




$orderBy = "FirstName";
$order = "asc";

 if(!empty($_GET["orderby"])) {
$orderBy = $_GET["orderby"];
}
if(!empty($_GET["order"])) {
$order = $_GET["order"];
}

$firstOrder = "asc";
$SurOrder = "asc";
$emailOrder = "desc";

if($orderBy == "FirstName" and $order == "asc") {
    $firstOrder = "desc";
}
if($orderBy == "Surname" and $order == "asc") {
    $surOrder = "desc";
}
if($orderBy == "Email" and $order == "desc") {
    $emailOrder = "asc";
}

// Build an SQL Query
$sql = "SELECT * from contacts ORDER BY " . $orderBy . " " . $order;


// Run the Query
$query = mysqli_query($db,$sql);

}

?>



    <form action="front-contact.php" method="post">
    <input type="text" name="valueToSearch" placeholder="Value To Search"><br><br>
    <input type="submit" name="search" value="Filter"><br><br>

    <form action='' method=post>
    <table border='1'>
    <tr>
    <th><a href="?orderby=FirstName&order=<?php echo $firstOrder; ?>">First Name</a></th>
    <th><a href="?orderby=Surname&order=<?php echo $surOrder; ?>">Surname</th>
    <th><a href="?orderby=Email&order=<?php echo $emailOrder; ?>">Email Address</th>
    <th>Home Number</th>
    <th>Mobile Number</th>
    </tr>

  <?php




        // Loop through each returned record and store the data in $row.. // 
    while ($row = mysqli_fetch_assoc($query)) {


    // Output the column-name of $row using the array-notation // 

        echo "<form action='' method=post>";
        echo "<tr>";
        echo "<td>".$row['FirstName']."</td>";
        echo "<td>".$row['Surname']."</td>";
        echo "<td>".$row['Email']."</td>";
        echo "<td>".$row['HomePhone']."</td>";
        echo "<td>".$row['MobPhone']."</td>";
        echo " </form>";
        echo "</tr>";

    }

       echo "</table>";


?>

Answer 1

这更有意义。谢谢你的澄清。我想知道如果您使用搜索查询填充

valueToSearch

输入，它是否会在您排序时保留搜索结果。像这样的东西：

<input type="text" name="valueToSearch" placeholder="Value To Search" value="<?php echo isset($valueToSearch) ? $valueToSearch : '' ?>">

在您进行初始搜索时，输入很可能会被清除，因此当您对表进行排序时，它会重新查询您的数据库，但由于输入为空，因此它会再次提取所有数据库记录。这就是我的想法。如果它不起作用，请告诉我。

Answer 2

如何在这里搜索过滤表

$servername = "localhost";
$username = "root";
$password = "";
$dbName = "multi_login";
$con = new mysqli($servername, $username, $password, $dbName);
if ($con->connect_error) {
    die("Connection failed:" . $con->connect_error);
}
while ($row = $result->fetch_object()) {
    $total = $row->salary * $row->tax;  
    echo '<tr>
            <td>' . $row->id . '</td>
            <td>' . $row->name . '</td>
            <td>' . $row->sex . '</td>
            <td>' . $row->date . '</td>
            <td>' . $row->salary . '</td>
            <td>' . $row->tax . '</td>
            <td>' . $total . '</td>
            <td>