非模板类 C++ 中的构造函数模板

Question

我有一个非模板类（Uart），想要创建模板构造函数。它需要采用另一个模板类对象（SafeQueue）。然后这个构造函数将调用类中定义的另一个模板函数。

下面给出了类签名；

class UartCommunication
{
public:
    UartCommunication(const char *port, speed_t baudRate);

    template <typename SendStruct, typename ReceiveStruct, typename SendQueue = SafeQueue<SendStruct>, typename ReceiveQueue = SafeQueue<ReceiveStruct>>
    UartCommunication(const char* port, speed_t baudRate, 
                                        SendQueue& sendQueue, ReceiveQueue& receiveQueue,
                                        int pollingTime, bool sendIfReceived)
    {
        port_ = port;
        baudRate_ = baudRate;

        serial_fd_ = open(port_, O_RDWR | O_NOCTTY | O_NDELAY);
        if (serial_fd_ == -1)
        {
            std::cerr << "Error opening serial port" << std::endl;
            // Handle error
        }
        std::cout << "serial_fd_:" << serial_fd_ << std::endl;
        ConfigureSerialPort();

        // Start a thread to receive data
        receiveThread_ = std::thread(&SendAndReceiveStruct<SendStruct, ReceiveStruct>, this, 
                                                sendQueue, receiveQueue, pollingTime, sendIfReceived);
    }
    // SentAndReceiveStruct from UART
    template <typename SendStruct, typename ReceiveStruct, typename SendQueue = SafeQueue<SendStruct>, typename ReceiveQueue = SafeQueue<ReceiveStruct>>
    void SendAndReceiveStruct(SendQueue& sendQueue, ReceiveQueue& receiveQueue, int pollingTime, bool sendIfReceived)
    {
     ///codes
    }
}

///

// A threadsafe-queue.
template <class T>
class SafeQueue
{
}

我可以构建代码，而无需使用模板 const 从 Uart 类创建任何对象。实际上SendAndReceiveStruct函数与const具有相同的签名，并且可以在线程函数中调用。但是当我尝试用类似的方式创建一个Uart对象时；

UartCommunication<InputStruct, OutputStruct> pcUart("/dev/ttyUSB0", B921600, AlgoTester::safeQueueInstanceAlgoInput, AlgoTester::safeQueueInstanceAlgoOutput, 20, false);

我明白了 类“UartCommunication”可能没有模板参数列表C/C++(519) “UartCommunication”不是 templateGCC 错误。我提供了 SafeQueue 实例的模板，但是这样使用它是否含糊不清？我需要使用safequeue模板作为对象，所以我不能直接使用safequeue对象作为模板。

感谢您的帮助。

Answer 1

auto pcUart = UartCommunication<InputStruct, OutputStruct>("/dev/ttyUSB0", B921600, AlgoTester::safeQueueInstanceAlgoInput, AlgoTester::safeQueueInstanceAlgoOutput, 20, false);

或者

UartCommunication pcUart = UartCommunication<InputStruct, OutputStruct>("/dev/ttyUSB0", B921600, AlgoTester::safeQueueInstanceAlgoInput, AlgoTester::safeQueueInstanceAlgoOutput, 20, false);