我有这样一张桌子:
+------+-----------+
|caseID|groupVarian|
+------+-----------+
|1 |A,B,C,D,E |
+------+-----------+
|2 |A,B,N,O,P |
+------+-----------+
|3 |A,B,N,O,P |
+------+-----------+
|4 |A,B,C,D,F |
+------+-----------+
|5 |A,B,C,D,E |
+------+-----------+
我想得到一个新的列nameVarian
,使得相同的groupVarian
值具有由nameVarian
表示的相同排名(例如:v1,v2等)。但是,分配给特定nameVarian
的groupVarian
值应该按照caseID
的顺序排列(按照它们出现在表格中的顺序)。
输出应该是这样的:
+------+-----------+----------+
|caseID|groupVarian|namevarian
+------+-----------+----------+
|1 |A,B,C,D,E |v1 |
+------+-----------+----------+
|2 |A,B,N,O,P |v2 |
+------+-----------+----------+
|3 |A,B,N,O,P |v2 |
+------+-----------+----------+
|4 |A,B,C,D,F |v3 |
+------+-----------+----------+
|5 |A,B,C,D,E |v1 |
+------+-----------+----------+
对于MySQL版本<8.0(OP's version is 5.6):
问题陈述看起来需要DENSE_RANK上的groupVarian
功能;但事实并非如此。 As explained by @Gordon Linoff:
您似乎希望按照它们在数据中出现的顺序枚举它们。
假设您的表名是t
(请根据您的代码更改表和字段名称)。这是一个approach utilizing session variables(对于旧版本的MySQL),给出了期望的结果(DB Fiddle):
SET @row_number = 0;
SELECT t3.caseID,
t3.groupVarian,
CONCAT('v', t2.num) AS nameVarian
FROM
(
SELECT
(@row_number:=@row_number + 1) AS num,
t1.groupVarian
FROM
(
SELECT DISTINCT groupVarian
FROM t
ORDER BY caseID ASC
) AS t1
) AS t2
INNER JOIN t AS t3
ON t3.groupVarian = t2.groupVarian
ORDER BY t3.caseID ASC
另外:我之前尝试模仿DENSE_RANK
功能,效果很好。虽然以前的查询也可以稍微调整,以实现DENSE_RANK
功能。但是,以下查询更有效,因为它创建较小的派生表,并避免在groupVarian
上加入:
SET @row_number = 1;
SET @group_varian = '';
SELECT inner_nest.caseID,
inner_nest.groupVarian,
CONCAT('v', inner_nest.num) as nameVarian
FROM (
SELECT
caseID,
@row_number:=CASE
WHEN @group_varian = groupVarian THEN @row_number
ELSE @row_number + 1
END AS num,
@group_varian:=groupVarian as groupVarian
FROM
t
ORDER BY groupVarian
) AS inner_nest
ORDER BY inner_nest.caseID ASC
你可以使用DENSE_RANK
(MySQL 8.0):
SELECT *, CONCAT('v', DENSE_RANK() OVER(ORDER BY groupVarian)) AS namevarian
FROM tab
ORDER BY CaseID;
基本上,您想要枚举变体。如果您只想要一个数字,那么您可以使用最小ID:
select t.*, min_codeId as groupVariantId
from t join
(select groupVariant, min(codeId) as min_codeId
from t
group by groupVariant
) g
on t.groupVariant = g.groupVariant;
但那不是你想要的。您似乎希望按照它们在数据中出现的顺序枚举它们。为此,您需要变量。这有点棘手,但是:
select t.*, rn as groupVariantId
from t join
(select g.*,
(@rn := if(@gv = groupvariant, @gv,
if(@gv := groupvariant, @gv+1, @gv+1)
)
) as rn
from (select groupVariant, min(codeId) as min_codeId
from t
group by groupVariant
order by min(codeId)
) g cross join
(select @gv := '', @rn := 0) params
) g
on t.groupVariant = g.groupVariant;
使用变量很棘手。一个重要的考虑因素:MySQL不保证SELECT
中表达式的评估顺序。这意味着变量不应该在一个表达式中分配,然后在另一个表达式中使用 - 因为它们可能以错误的顺序进行评估(另一个答案有这个错误)。
此外,order by
需要在子查询中进行。 MySQL不保证在排序之前发生变量赋值。