SELECT
1+(SELECT count(*) from games a WHERE a.score > g.score) as rank,
score, p.leaderboard_initials, p.operating_system
FROM games g
inner join players p on (p.google_id = g.google_id)
ORDER BY score DESC
LIMIT 0, 100;
返回为玩家提供每场比赛的排行榜。
我需要返回一个排行榜,其中只列出每个玩家的最佳得分游戏。所以44rhh
仍将位居榜首,其次是DMC
,但随后BMO
将排在第三位。
我知道解决方案应该很简单,但我想不出怎么做!
您可以通过leaderboard_initials选择最高分数组
您可以通过leaderboard_initials选择最高分数组
set @rank=0;
select (@rank:=@rank+1) rank , leaderboard_initials, max(score) max_score
from (
SELECT
1+(SELECT count(*)
from games a WHERE a.score > g.score) as rank,
score, p.leaderboard_initials, p.operating_system
FROM games g
inner join players p on (p.google_id = g.google_id)
ORDER BY score DESC
LIMIT 0, 100;
) t
group by leaderboard_initials
order by max_score DESC