如何在Java中转换Youtube API V3持续时间

Question

Youtube V3 API使用ISO8601时间格式来描述视频的持续时间。有点像“PT1M13S”。现在我想将字符串转换为秒数（例如在这种情况下为73）。

是否有任何Java库可以帮助我轻松完成Java 6下的任务？或者我必须自己做正则表达式的任务？

编辑

最后，我接受@Joachim Sauer的回答

Joda的示例代码如下。

PeriodFormatter formatter = ISOPeriodFormat.standard();
Period p = formatter.parsePeriod("PT1H1M13S");
Seconds s = p.toStandardSeconds();

System.out.println(s.getSeconds());

Answer 1

Joda Time是任何类型的时间相关功能的首选图书馆。

对于这个特定情况，ISOPeriodFormat.standard()返回一个可以解析和格式化该格式的PeriodFormatter。

产生的对象是a Period（JavaDoc）。获得实际的秒数将是period.toStandardSeconds().getSeconds()，但我建议您只需将持续时间作为Period对象处理（为了便于处理和类型安全）。

编辑：未来我的一个注释：这个答案现在好几年了。 Java 8带来了java.time.Duration，它也可以解析这种格式，不需要外部库。

Answer 2

而另一个很长的路要做同样的事情。

private String getTimeFromString(String duration) {
    // TODO Auto-generated method stub
    String time = "";
    boolean hourexists = false, minutesexists = false, secondsexists = false;
    if (duration.contains("H"))
        hourexists = true;
    if (duration.contains("M"))
        minutesexists = true;
    if (duration.contains("S"))
        secondsexists = true;
    if (hourexists) {
        String hour = "";
        hour = duration.substring(duration.indexOf("T") + 1,
                duration.indexOf("H"));
        if (hour.length() == 1)
            hour = "0" + hour;
        time += hour + ":";
    }
    if (minutesexists) {
        String minutes = "";
        if (hourexists)
            minutes = duration.substring(duration.indexOf("H") + 1,
                    duration.indexOf("M"));
        else
            minutes = duration.substring(duration.indexOf("T") + 1,
                    duration.indexOf("M"));
        if (minutes.length() == 1)
            minutes = "0" + minutes;
        time += minutes + ":";
    } else {
        time += "00:";
    }
    if (secondsexists) {
        String seconds = "";
        if (hourexists) {
            if (minutesexists)
                seconds = duration.substring(duration.indexOf("M") + 1,
                        duration.indexOf("S"));
            else
                seconds = duration.substring(duration.indexOf("H") + 1,
                        duration.indexOf("S"));
        } else if (minutesexists)
            seconds = duration.substring(duration.indexOf("M") + 1,
                    duration.indexOf("S"));
        else
            seconds = duration.substring(duration.indexOf("T") + 1,
                    duration.indexOf("S"));
        if (seconds.length() == 1)
            seconds = "0" + seconds;
        time += seconds;
    }
    return time;
}

Answer 3

我已经编写并使用此方法来获取实际持续时间。希望这可以帮助。

private String timeHumanReadable (String youtubeTimeFormat) {
// Gets a PThhHmmMssS time and returns a hh:mm:ss time

    String
            temp = "",
            hour = "",
            minute = "",
            second = "",
            returnString;

    // Starts in position 2 to ignore P and T characters
    for (int i = 2; i < youtubeTimeFormat.length(); ++ i)
    {
        // Put current char in c
        char c = youtubeTimeFormat.charAt(i);

        // Put number in temp
        if (c >= '0' && c <= '9')
            temp = temp + c;
        else
        {
            // Test char after number
            switch (c)
            {
                case 'H' : // Deal with hours
                    // Puts a zero in the left if only one digit is found
                    if (temp.length() == 1) temp = "0" + temp;

                    // This is hours
                    hour = temp;

                    break;

                case 'M' : // Deal with minutes
                    // Puts a zero in the left if only one digit is found
                    if (temp.length() == 1) temp = "0" + temp;

                    // This is minutes
                    minute = temp;

                    break;

                case  'S': // Deal with seconds
                    // Puts a zero in the left if only one digit is found
                    if (temp.length() == 1) temp = "0" + temp;

                    // This is seconds
                    second = temp;

                    break;

            } // switch (c)

            // Restarts temp for the eventual next number
            temp = "";

        } // else

    } // for

    if (hour == "" && minute == "") // Only seconds
        returnString = second;
    else {
        if (hour == "") // Minutes and seconds
            returnString = minute + ":" + second;
        else // Hours, minutes and seconds
            returnString = hour + ":" + minute + ":" + second;
    }

    // Returns a string in hh:mm:ss format
    return returnString; 

}

Answer 4

时间已经格式化，所以看起来只是替换就足够了。

import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;
import java.util.

public class YouTubeDurationUtils {
    /**
     * 
     * @param duration
     * @return "01:02:30"
     */
    public static String convertYouTubeDuration(String duration) {
        String youtubeDuration = duration; //"PT1H2M30S"; // "PT1M13S";
        Calendar c = new GregorianCalendar();
        try {
            DateFormat df = new SimpleDateFormat("'PT'mm'M'ss'S'");
            Date d = df.parse(youtubeDuration);
            c.setTime(d);
        } catch (ParseException e) {
            try {
                DateFormat df = new SimpleDateFormat("'PT'hh'H'mm'M'ss'S'");
                Date d = df.parse(youtubeDuration);
                c.setTime(d);
            } catch (ParseException e1) {
                try {
                    DateFormat df = new SimpleDateFormat("'PT'ss'S'");
                    Date d = df.parse(youtubeDuration);
                    c.setTime(d);
                } catch (ParseException e2) {
                }
            }
        }
        c.setTimeZone(TimeZone.getDefault());

        String time = "";
        if ( c.get(Calendar.HOUR) > 0 ) {
            if ( String.valueOf(c.get(Calendar.HOUR)).length() == 1 ) {
                time += "0" + c.get(Calendar.HOUR);
            }
            else {
                time += c.get(Calendar.HOUR);
            }
            time += ":";
        }
        // test minute
        if ( String.valueOf(c.get(Calendar.MINUTE)).length() == 1 ) {
            time += "0" + c.get(Calendar.MINUTE);
        }
        else {
            time += c.get(Calendar.MINUTE);
        }
        time += ":";
        // test second
        if ( String.valueOf(c.get(Calendar.SECOND)).length() == 1 ) {
            time += "0" + c.get(Calendar.SECOND);
        }
        else {
            time += c.get(Calendar.SECOND);
        }
        return time ;
    }
}

Answer 5

使用// PT1H9M24S --> 1:09:24 // PT2H1S" --> 2:00:01 // PT23M2S --> 23:02 // PT31S --> 0:31 public String convertDuration(String duration) { duration = duration.substring(2); // del. PT-symbols String H, M, S; // Get Hours: int indOfH = duration.indexOf("H"); // position of H-symbol if (indOfH > -1) { // there is H-symbol H = duration.substring(0,indOfH); // take number for hours duration = duration.substring(indOfH); // del. hours duration = duration.replace("H",""); // del. H-symbol } else { H = ""; } // Get Minutes: int indOfM = duration.indexOf("M"); // position of M-symbol if (indOfM > -1) { // there is M-symbol M = duration.substring(0,indOfM); // take number for minutes duration = duration.substring(indOfM); // del. minutes duration = duration.replace("M",""); // del. M-symbol // If there was H-symbol and less than 10 minutes // then add left "0" to the minutes if (H.length() > 0 && M.length() == 1) { M = "0" + M; } } else { // If there was H-symbol then set "00" for the minutes // otherwise set "0" if (H.length() > 0) { M = "00"; } else { M = "0"; } } // Get Seconds: int indOfS = duration.indexOf("S"); // position of S-symbol if (indOfS > -1) { // there is S-symbol S = duration.substring(0,indOfS); // take number for seconds duration = duration.substring(indOfS); // del. seconds duration = duration.replace("S",""); // del. S-symbol if (S.length() == 1) { S = "0" + S; } } else { S = "00"; } if (H.length() > 0) { return H + ":" + M + ":" + S; } else { return M + ":" + S; } }网站：

private String parseDuration(String duration) {
    duration = duration.contains("PT") ? duration.replace("PT", "") : duration;
    duration = duration.contains("S") ? duration.replace("S", "") : duration;
    duration = duration.contains("H") ? duration.replace("H", ":") : duration;
    duration = duration.contains("M") ? duration.replace("M", ":") : duration;
    String[] split = duration.split(":");
    for(int i = 0; i< split.length; i++){
        String item = split[i];
        split[i] = item.length() <= 1 ? "0"+item : item;
    }
    return TextUtils.join(":", split);
}

Answer 6

问题private String stringForTime(String ytFormattedTime) { return ytFormattedTime .replace("PT","") .replace("H",":") .replace("M",":") .replace("S",""); }包含另一个解决方案：

更简单的解决方案可能是在JAXB中使用数据类型转换器，因为JAXB必须能够根据XML Schema规范解析ISO8601日期字符串。 this会给你一个// URL that generated this code: // http://txt2re.com/index-java.php3?s=PT1M13S&6&3&18&20&-19&-21 import java.util.regex.*; class Main { public static void main(String[] args) { String txt="PT1M13S"; String re1="(P)"; // Any Single Character 1 String re2="(T)"; // Any Single Character 2 String re3="(\\d+)"; // Integer Number 1 String re4="(M)"; // Any Single Character 3 String re5="(\\d+)"; // Integer Number 2 String re6="(S)"; // Any Single Character 4 Pattern p = Pattern.compile(re1+re2+re3+re4+re5+re6,Pattern.CASE_INSENSITIVE | Pattern.DOTALL); Matcher m = p.matcher(txt); if (m.find()) { String c1=m.group(1); String c2=m.group(2); String minutes=m.group(3); // Minutes are here String c3=m.group(4); String seconds=m.group(5); // Seconds are here String c4=m.group(6); System.out.print("("+c1.toString()+")"+"("+c2.toString()+")"+"("+minutes.toString()+")"+"("+c3.toString()+")"+"("+seconds.toString()+")"+"("+c4.toString()+")"+"\n"); int totalSeconds = Integer.parseInt(minutes) * 60 + Integer.parseInt(seconds); } } }对象，如果你需要一个Converting ISO 8601-compliant String to java.util.Date对象，你可以简单地使用javax.xml.bind.DatatypeConverter.parseDateTime("2010-01-01T12:00:00Z")。

Answer 7

我可能会迟到，这实际上非常简单。虽然可能有更好的方法来做到这一点。持续时间以毫秒为单位。

public long getDuration() {
    String time = "PT15H12M46S".substring(2);
    long duration = 0L;
    Object[][] indexs = new Object[][]{{"H", 3600}, {"M", 60}, {"S", 1}};
    for(int i = 0; i < indexs.length; i++) {
        int index = time.indexOf((String) indexs[i][0]);
        if(index != -1) {
            String value = time.substring(0, index);
            duration += Integer.parseInt(value) * (int) indexs[i][1] * 1000;
            time = time.substring(value.length() + 1);
        }
    }
    return duration;
}

Answer 8

Java 8中的解决方案：

Duration.parse(duration).getSeconds()

Answer 9

这是我的解决方案

public class MyDateFromat{
    public static void main(String args[]){
        String ytdate = "PT1H1M15S";
        String result = ytdate.replace("PT","").replace("H",":").replace("M",":").replace("S","");
        String arr[]=result.split(":");
        String timeString = String.format("%d:%02d:%02d", Integer.parseInt(arr[0]), Integer.parseInt(arr[1]),Integer.parseInt(arr[2]));
        System.out.print(timeString);       
    }
}

如果要在几秒钟内转换，它将返回H：MM：SS格式的字符串

int timeInSedonds = int timeInSecond = Integer.parseInt(arr[0])*3600 + Integer.parseInt(arr[1])*60 +Integer.parseInt(arr[2])

注意：它可以抛出异常，所以请根据result.split（“：”）的大小来处理它。

Answer 10

您可以使用标准的qazxsw poi将qazxsw poi解析为qazxsw poi并从那里处理它：

SimpleDateFormat

Answer 11

如果您可以非常确定输入的有效性并且不能使用正则表达式，我使用此代码（以毫秒为单位返回）：

String

Answer 12

可能这会帮助一些不想要任何图书馆而只是简单功能的人，

Date

这是功能，

DateFormat df = new SimpleDateFormat("'PT'mm'M'ss'S'");
String youtubeDuration = "PT1M13S";
Date d = df.parse(youtubeDuration);
Calendar c = new GregorianCalendar();
c.setTime(d);
c.setTimeZone(TimeZone.getDefault());
System.out.println(c.get(Calendar.MINUTE));
System.out.println(c.get(Calendar.SECOND));

Answer 13

我已经实现了这个方法，它到目前为止已经有效了。

Integer parseYTDuration(char[] dStr) {
    Integer d = 0;

    for (int i = 0; i < dStr.length; i++) {
        if (Character.isDigit(dStr[i])) {
            String digitStr = "";
            digitStr += dStr[i];
            i++;
            while (Character.isDigit(dStr[i])) {
                digitStr += dStr[i];
                i++;
            }

            Integer digit = Integer.valueOf(digitStr);

            if (dStr[i] == 'H')
                d += digit * 3600;
            else if (dStr[i] == 'M')
                d += digit * 60;
            else
                d += digit;
        }
    }

    return d * 1000;
}

Answer 14

我自己做了

我们试试吧

String duration="PT1H11M14S";

如何在Java中转换Youtube API V3持续时间

问题描述投票：18回答：14

14个回答

最新问题

如何在Java中转换Youtube API V3持续时间

问题描述 投票：18回答：14

14个回答

最新问题

问题描述投票：18回答：14