SQL查询拓扑排序

问题描述 投票:0回答:1

我有向无环图:

DROP TABLE IF EXISTS #Edges
CREATE TABLE #Edges(from_node int, to_node int);
INSERT INTO #Edges VALUES (1,2),(1,3),(1,4),(5,1);

enter image description here

我想列出所有节点,总是在它的from节点之前列出一个to节点。例如:2、3、4、1、5。

也称为拓扑排序。如何在SQL中完成?

sql sql-server graph-algorithm graph-traversal topological-sort
1个回答
0
投票

您可以使用递归CTE来计算深度。然后按深度排序:

with cte as (
      select e.from_node, e.to_node, 1 as lev
      from edges e
      where not exists (select 1 from edges e2 where e2.to_node = e.from_node)
      union all
      select e.from_node, e.to_node, lev + 1
      from cte join
           edges e
           on e.from_node = cte.to_node
     )
select *
from cte
order by lev desc;
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