我有一个管道,对于我所需要的东西来说非常好......但我认为有一些冗余的数据可以从管道中删除。
这就是我想要的输出结果的样子
{
"_id": "5ecee2189fdd1b0004056936",
"name": "Mike",
"history": [
{
"_id": "5ecb263c166b8500047c1411",
"what": "Log IN"
},
{
"_id": "5ecb263c166b8500047c1422",
"what": "Log OUT"
}
]
}
这就是目前的输出情况
{
"docs": [
{
"_id": "5ecee2189fdd1b0004056936",
"name": "Mike",
"history": {
"_id": "5ecb263c166b8500047c1411",
"what": "Log IN"
},
"historyIndex": 0
},
{
"_id": "5ecee2189fdd1b0004056936",
"name": "Mike",
"history": {
"_id": "5ecb263c166b8500047c1422",
"what": "Log OUT"
},
"historyIndex": 1
}
]
}
在现实生活中,会有比这更多的用户......当然......。
{
"_id": "5ecee2189fdd1b0004056936",
"name": "Mike",
}
再次,为了简单,我将数据保持在简短的范围内
[
{
"_id": "5ecb263c166b8500047c1411",
"userId": "5ecee2189fdd1b0004056936",
"what": "Log IN"
},
{
"_id": "5ecb263c166b8500047c1422",
"userId": "5ecee2189fdd1b0004056999",
"what": "Log IN"
},
{
"_id": "5ecb263c166b8500047c1433",
"userId": "5ecee2189fdd1b0004056936",
"what": "Log OUT"
},
{
"_id": "5ecb263c166b8500047c1444",
"userId": "5ecee2189fdd1b0004056999",
"what": "Log OUT"
}
]
我也在使用mongoose-aggregate-paginat-v2,但我不知道该怎么做。认为 这是我的问题,但当结果返回时,它肯定会发挥作用。它需要将文档扁平化,这样它就可以对它们进行计数和分页。
"totalDocs": 941,
"limit": 500,
"page": 1,
"totalPages": 2,
"pagingCounter": 1,
"hasPrevPage": false,
"hasNextPage": true,
"prevPage": null,
"nextPage": 2
这是我的流水线
var agg_match = {
$match:
{
_id: mongoose.Types.ObjectId(userId)
}
};
var agg_lookup = {
$lookup: {
from: 'it_userhistories',
localField: '_id',
foreignField: 'userId',
as: 'history'
}
}
var agg_unwind = {
$unwind: {
path: "$history",
preserveNullAndEmptyArrays: true,
includeArrayIndex: 'historyIndex',
}
}
var agg = [
agg_match,
agg_lookup,
agg_unwind,
agg_project,
];
var pageAndLimit = {
page:page,
limit:limit
}
User.aggregatePaginate(myAggregate, pageAndLimit)
你可以使用 $map
操作符来完成这个任务。下面的查询会很有帮助(我没有在管道中包含匹配阶段,你可以很容易地包含它)。
db.user.aggregate([
{
$lookup: {
from: "history",
localField: "_id",
foreignField: "userId",
as: "history"
}
},
{
$project: {
name: 1,
history: {
$map: {
input: "$history",
as: "h",
in: {
_id: "$$h._id",
what: "$$h.what"
}
}
}
}
}
])