我想为一个动态读取值的Object的每个Property创建一个Lambda Expression。
到目前为止我所拥有的:
var properties = typeof (TType).GetProperties().Where(p => p.CanRead);
foreach (var propertyInfo in properties)
{
var getterMethodInfo = propertyInfo.GetGetMethod();
var entity = Expression.Parameter(typeof (TType));
var getterCall = Expression.Call(entity, getterMethodInfo);
var lambda = Expression.Lambda(getterCall, entity);
var expression = (Expression<Func<TType, "TypeOfProperty">>) lambda;
var functionThatGetsValue = expression.Compile();
}
只要“TypeOfProperty”是硬编码的,当我调用functionThatGetsValue
时,代码运行良好。我知道我无法动态传递“TypeOfPoperty”。我能做些什么来实现我的目标?
假设您对Func<TType, object>
代表感到满意(根据上面的评论),您可以使用Expression.Convert
来实现:
var properties = typeof(TType).GetProperties().Where(p => p.CanRead);
foreach (var propertyInfo in properties)
{
MethodInfo getterMethodInfo = propertyInfo.GetGetMethod();
ParameterExpression entity = Expression.Parameter(typeof(TType));
MethodCallExpression getterCall = Expression.Call(entity, getterMethodInfo);
UnaryExpression castToObject = Expression.Convert(getterCall, typeof(object));
LambdaExpression lambda = Expression.Lambda(castToObject, entity);
var functionThatGetsValue = (Func<TType, object>)lambda.Compile();
}
经过几个小时的谷歌搜索找到答案here。我已经从博客文章中添加了片段,因为它可能会帮助其他人遇到同样的麻烦:
public static class PropertyInfoExtensions
{
public static Func<T, object> GetValueGetter<T>(this PropertyInfo propertyInfo)
{
if (typeof(T) != propertyInfo.DeclaringType)
{
throw new ArgumentException();
}
var instance = Expression.Parameter(propertyInfo.DeclaringType, "i");
var property = Expression.Property(instance, propertyInfo);
var convert = Expression.TypeAs(property, typeof(object));
return (Func<T, object>)Expression.Lambda(convert, instance).Compile();
}
public static Action<T, object> GetValueSetter<T>(this PropertyInfo propertyInfo)
{
if (typeof(T) != propertyInfo.DeclaringType)
{
throw new ArgumentException();
}
var instance = Expression.Parameter(propertyInfo.DeclaringType, "i");
var argument = Expression.Parameter(typeof(object), "a");
var setterCall = Expression.Call(
instance,
propertyInfo.GetSetMethod(),
Expression.Convert(argument, propertyInfo.PropertyType));
return (Action<T, object>)Expression.Lambda(setterCall, instance, argument).Compile();
}
}
我上面修改了gsharp的帖子,直接实际设置了值,使它更容易使用。由于DynamicCast功能的引入要求您事先了解您的类型,因此它并不理想。我的目标是尽量保持强类型,不返回对象,避免使用动态关键字。此外,将“魔力”保持在最低限度。
public static T DynamicCast<T>(this object value)
{
return (T) value;
}
public static object GetPropertyValue<T>(this PropertyInfo propertyInfo, T objectInstance)
{
if (typeof(T) != propertyInfo.DeclaringType)
{
throw new ArgumentException();
}
var instance = Expression.Parameter(propertyInfo.DeclaringType, "i");
var property = Expression.Property(instance, propertyInfo);
var convert = Expression.TypeAs(property, propertyInfo.PropertyType);
var lambda = Expression.Lambda(convert, instance).Compile();
var result = lambda.DynamicInvoke(objectInstance);
return result;
}
public static void SetPropertyValue<T, TP>(this PropertyInfo propertyInfo, T objectInstance, TP value)
where T : class
where TP : class
{
if (typeof(T) != propertyInfo.DeclaringType)
{
throw new ArgumentException();
}
var instance = Expression.Parameter(propertyInfo.DeclaringType, "i");
var argument = Expression.Parameter(propertyInfo.PropertyType, "a");
var setterCall = Expression.Call(
instance,
propertyInfo.GetSetMethod(),
Expression.Convert(argument, propertyInfo.PropertyType));
var lambda = Expression.Lambda(setterCall, instance, argument).Compile();
lambda.DynamicInvoke(objectInstance, value);
}
例子:
public void Get_Value_Of_Property()
{
var testObject = new ReflectedType
{
AReferenceType_No_Attributes = new object(),
Int32WithRange1_10 = 5,
String_Requires = "Test String"
};
var result = testObject.GetType().GetProperty("String_Requires").GetPropertyValue(testObject).DynamicCast<string>();
result.Should().Be(testObject.String_Requires);
}
public void Set_Value_Of_Property()
{
var testObject = new ReflectedType
{
AReferenceType_No_Attributes = new object(),
Int32WithRange1_10 = 5,
String_Requires = "Test String"
};
testObject.GetType().GetProperty("String_Requires").SetPropertyValue(testObject, "MAGIC");
testObject.String_Requires.Should().Be("MAGIC");
}
您可以编写一个帮助方法,该方法使用MakeGenericMethod或表达式树来使lambda执行类型化调用以基于PropertyInfo对象调用DynamicCast,并避免必须事先知道它。但那不那么优雅。